[R] graphs, need urgent help (deadline :( )
Don McKenzie
dmck at uw.edu
Thu Jun 11 04:07:45 CEST 2015
Thanks John! My eyes aren't good enough to see that. I actually checked (I thought). This was the default window on Mac console, for others who might care.
Sent from my iPad
> On Jun 10, 2015, at 6:17 PM, John Kane <jrkrideau at inbox.com> wrote:
>
> You have curly quotes rather than plain ones here : col=4,type=“l”,xlab=“Region”,ylab=“factor")
>
>
>
> John Kane
> Kingston ON Canada
>
> -----Original Message-----
> From: dmck at u.washington.edu
> Sent: Wed, 10 Jun 2015 11:32:59 -0700
> To: rosita21 at gmail.com
> Subject: Re: [R] graphs, need urgent help (deadline :( )
>
> You were caught by a mysterious issue that I don’t understand either.
>
> plot(therapy.df$Region[therapy.df$sample==50],therapy.df$factor.a[therapy.df$sample==50],col=4,type=“l”,xlab=“Region”,ylab=“factor")
>
> Error: unexpected input in "plot(therapy.df$Region[therapy.df$sample==50],therapy.df$factor.a[therapy.df$sample==50],col=4,type=‚”
>
> but if I change the order of arguments to plot(), it’s fine
>
> plot(therapy.df$Region[therapy.df$sample==50],therapy.df$factor.a[therapy.df$sample==50],type="l",col=4,xlab="Region",ylab="factor”)
>
> I don’t know what to tell you. If someone wiser than I is still reading, maybe s(he) can explain. Possibly a bug has crept into the call to “par”, but “bugs" suspected by non-experts like me usually turn out to be naive user errors.
>
> For your purposes, use the one that works. :-)
>
> On Jun 10, 2015, at 11:03 AM, Rosa Oliveira <rosita21 at gmail.com> wrote:
>
> Sorry,
>
> I taught I attached the cvs file :)
>
> <therapy.csv>
>
> Don,
>
> I tried, but I got an error:
>
>> my.data$Region
>
> [1] 1 2 3 4 5 6 7 8 9 10 1 2 3 4 5 6 7 8 9 10 1 2 3 4 5 6 7 8 9 10
>
>> my.data$sample
>
> [1] 50 50 50 50 50 50 50 50 50 50 250 250 250 250 250 250 250 250 250 250 1000 1000 1000 1000 1000 1000 1000 1000
>
> [29] 1000 1000
>
>> my.data$factor.a
>
> [1] 0.895 0.811 0.685 0.777 0.600 0.466 0.446 0.392 0.256 0.198 0.136 0.121 0.875 0.777 0.685 0.626 0.550 0.466 0.384 0.330 0.060 0.138 0.065
>
> [24] 0.034 0.931 0.124 0.060 0.028 0.017 0.014
>
>> plot(my.data$Region[my.data$sample==50],my.data$factor.a[my.data$sample==50],col=4,type=“l”,xlab=“Region”,ylab=“factor")
>
> Error: unexpected input in "plot(my.data$Region[my.data$sample==50],my.data$factor.a[my.data$sample==50],col=4,type=�”
>
> I’m really naive, right?
>
> Best,
>
> RO
>
> Atenciosamente,
> Rosa Oliveira
>
> --
> ____________________________________________________________________________
>
> <smile.jpg>
>
> Rosa Celeste dos Santos Oliveira,
>
> E-mail: rosita21 at gmail.com
> Tlm: +351 939355143
> Linkedin: https://pt.linkedin.com/in/rosacsoliveira [https://pt.linkedin.com/in/rosacsoliveira]
> ____________________________________________________________________________
>
> "Many admire, few know"
> Hippocrates
>
> On 10 Jun 2015, at 18:10, Don McKenzie <dmck at u.washington.edu> wrote:
>
> For a legend, try (untested)
>
> legend(0.15,0.9,c("factora","factorb","factorc"),col=c(4,2,3),lty=1)
>
> If it overlaps data points move the first two arguments (0.15 and 0.9) around, or change the “ylim” argument in the plot() to ~1.2.
>
> to avoid clutter, put the line-types information in the figure caption (IMO)
>
> On Jun 10, 2015, at 10:03 AM, Don McKenzie <dmck at u.washington.edu> wrote:
>
> On Jun 10, 2015, at 9:08 AM, Rosa Oliveira <rosita21 at gmail.com> wrote:
>
> Dear All,
>
> I attach my data.
>
> Dear Jim,
>
> when I run your code (even the one you send me, not in my data), I get:
>
> Don't know how to automatically pick scale for object of type function. Defaulting to continuous
>
> Error in data.frame(x = c(0.1, 0.2, 0.1, 0.2, 0.1, 0.2, 0.1, 0.2, 0.1, :
>
> arguments imply differing number of rows: 24, 0
>
> Dear Don,
>
> It’s meant that I will have 12 lines:
>
> 3 factors - lines colors
>
> with 3 different values of “sample” for each - line types
>
> [Three colors, one for each factor,
> and three line types (lty=1,2,3), one for eachvalue of “sample - preferable dash, thin and thick).
>
> in the X - I should have region (because I have 10 regions)
>
> for each region I have the outcome of 3 different treatments (factor)
>
> for each region and each treatment I have 3 different sample size.
>
> But in your original post you had 4 sample sizes: 10,20,30,40.
>
> I need to “see” the the influence of the region in the treatment outcome for each sample size.
>
> So, at the end I should have 9 lines
>
> 3 red (1 dash, 1 thin, 1 thick) - concerning factor a (dash for sample size 50, thin for sample size 250 and thick for sample size 1000)
>
> 3 blue (1 dash, 1 thin, 1 thick) - concerning factor b (dash for sample size 50, thin for sample size 250 and thick for sample size 1000)
>
> 3 green (1 dash, 1 thin, 1 thick) - concerning factor c (dash for sample size 50, thin for sample size 250 and thick for sample size 1000)
>
> Hope this time is clear.
>
> I also though about doing 3 different graphs, each one for 1 different sample size, and in that case I should have 3 graphs each one with 3 lines
>
> 1 red to factor a, 1 blue to factor b and 1 green to factor c.
>
> Do you all think is better?
>
> A matter of style perhaps but I would use dotplots because you have only two data points for each “line”. The lines will be misleading. You also could use
>
> panel plots, but given your skill set (unless someone wants to spend a fair bit of time with you), it’s probably best to stay as simple as possible.
>
> But given your original post (cleaned up) # untested: apologies for any typos
>
> region sample factora factorb factorc
> 0.1 10 0.895 0.903 0.378
> 0.2 10 0.811 0.865 0.688
> 0.1 20 0.735 0.966 0.611
> 0.2 20 0.777 0.732 0.653
> 0.1 30 0.600 0.778 0.694
> 0.2 30 0.466 174.592 0.461
> 0.1 40 0.446 0.432 0.693
>
> 0.2 40 0.392 0.294 0.686
>
> plot(my.data$region[my.data$sample==10],my.data$factora[my.data$sample==10],col=4,type=“l”,ylim=c(0,1),xlab=“region”,ylab=“factor")
>
> lines(my.data$region[my.data$sample==10],my.data$factorb[my.data$sample==10],col=2)
>
> lines(my.data$region[my.data$sample==10],my.data$factorc[my.data$sample==10],col=3)
>
> lines(my.data$region[my.data$sample==20],my.data$factora[my.data$sample==20],col=4,lty=2)
>
> lines(my.data$region[my.data$sample==20],my.data$factorb[my.data$sample==20],col=2,lty=2)
>
> lines(my.data$region[my.data$sample==20],my.data$factorc[my.data$sample==20],col=3,lty=2)
>
> # Now do two more groups of 3, changing the parameter “lty” to 3 and then 4
>
> # Look at the syntax and note what changes and what stays constant. Do you see how this works?
>
> # there will be what looks like a vertical line where sample = 30 and factorb = 174.592. Do you see why?
>
> # then you will need a legend
>
> Nonetheless I can’t do it :(
>
> best,
>
> RO
>
> Atenciosamente,
> Rosa Oliveira
>
> --
> ____________________________________________________________________________
>
> <smile.jpg>
> Rosa Celeste dos Santos Oliveira,
>
> E-mail: rosita21 at gmail.com
> Tlm: +351 939355143
> Linkedin: https://pt.linkedin.com/in/rosacsoliveira [https://pt.linkedin.com/in/rosacsoliveira]
> ____________________________________________________________________________
>
> "Many admire, few know"
> Hippocrates
>
> On 10 Jun 2015, at 14:13, John Kane <jrkrideau at inbox.com> wrote:
>
> Hi Jim,
>
> I was looking at that last night and had the same problem of visualizing what Rosa needed.
>
> Hi Rosa
> This is nothing like what you wanted and I really don't understand your data but would something like this work as a substitute or am I completely lost?
>
> dat1 <- structure(list(region = c(0.1, 0.2, 0.1, 0.2, 0.1, 0.2, 0.1,
> 0.2), sample = c(10L, 10L, 20L, 20L, 30L, 30L, 40L, 40L), factora = c(0.895,
> 0.811, 0.735, 0.777, 0.6, 0.466, 0.446, 0.392), factorb = c(0.903,
> 0.865, 0.966, 0.732, 0.778, 0.592, 0.432, 0.294), factorc = c(0.37,
> 0.688, 0.611, 0.653, 0.694, 0.461, 0.693, 0.686)), .Names = c("region",
> "sample", "factora", "factorb", "factorc"), class = "data.frame", row.names = c(NA,
> -8L))
>
> mdat1 <- melt(dat1, id.var = c("region", "sample"),
> variable.name = "factor",
> value.name = "value")
> str(mdat1)
>
> ggplot(mdat1, aes(region, value, colour = factor)) +
> geom_line() + facet_grid(sample ~ .)
>
> John Kane
> Kingston ON Canada
>
> -----Original Message-----
> From: drjimlemon at gmail.com
> Sent: Wed, 10 Jun 2015 20:51:52 +1000
> To: rosita21 at gmail.com
> Subject: Re: [R] graphs, need urgent help (deadline :( )
>
> Hi Rosa,
> Like Don, I can't work out what you want and I don't even have the
> picture. For example, your specification of color and line type leaves
> only one point for each color and line type, and the line from one
> point to the same point is not going to show up. Here is a possibility
> that may lead (eventually) to a solution.
>
> library(plotrix)
> par(tcl=-0.1)
> gap.plot(x=rep(seq(10,45,by=5),3),
> y=unlist(my.data[,c("factora","factorb","factorc")]),
> main="A plot of factorial mystery",
> gap=c(1.1,174),ylim=c(0,175),ylab="factor score",xlab="Group",
> xticlab=c(" \n0.1\n10"," \n0.2\n10"," \n0.1\n20"," \n0.2\n20",
> " \n0.1\n30"," \n0.2\n30"," \n0.1\n40"," \n0.2\n40"),
> ytics=c(0,0.5,1,174.59),pch=rep(1:3,each=8),col=rep(c(4,2,3),each=8))
> mtext(c("Region","Sample"),side=1,at=6,line=c(0,1))
> lines(seq(10,45,by=5),my.data$factora,col=4)
> lines(seq(10,45,by=5),my.data$factorb[c(1:5,NA,7,8)],col=2)
> lines(seq(10,45,by=5),my.data$factorc,col=3)
>
> Jim
>
> On Wed, Jun 10, 2015 at 10:53 AM, Rosa Oliveira <rosita21 at gmail.com>
> wrote:
>
> Dear Don and all,
>
> I’ve read the tutorial and tried several codes before posting :)
> I’m really naive.
>
> what I was trying to : is something like the graph in the picture I
> drawee.
>
> Is it more clear now?
>
> Atenciosamente,
> Rosa Oliveira
>
> --
> ____________________________________________________________________________
>
> Rosa Celeste dos Santos Oliveira,
>
> E-mail: rosita21 at gmail.com <mailto:rosita21 at gmail.com>
> Tlm: +351 939355143
> Linkedin: https://pt.linkedin.com/in/rosacsoliveira [https://pt.linkedin.com/in/rosacsoliveira]
> <https://pt.linkedin.com/in/rosacsoliveira [https://pt.linkedin.com/in/rosacsoliveira]>
> ____________________________________________________________________________
> "Many admire, few know"
> Hippocrates
>
> On 09 Jun 2015, at 19:23, Don McKenzie <dmck at u.washington.edu
> <mailto:dmck at u.washington.edu>> wrote:
>
> The answer lies in learning to use the help (and knowing where to
> start). Did you look at the tutorial that comes with the R
> installation?
>
> ?plot
> ?lines
>
> ?par
>
> In the last, look for the descriptions of “col” and “lty”.
>
> Using plot() and lines(), and subsetting the four unique values of
> “sample”, you can create your lines.
>
> Here is a crude start, assuming your columns are part of a data frame
> called “my.data”. Untested...
>
> plot(my.data$region[my.data$sample==10],my.data$factora[my.data$sample==10],col=4)
>
> # blue line, not dashed
> .
> .
> .
>
> lines(my.data$region[my.data$sample==20],my.data$factorb[my.data$sample==20],col=2,lty=2)
>
> # red dashed line
>
> On Jun 9, 2015, at 10:36 AM, Rosa Oliveira <rosita21 at gmail.com
> <mailto:rosita21 at gmail.com>> wrote:
>
> Hi,
>
> another naive question (i’m pretty sure :( )
>
> I’m trying to plot a multiple line graph:
>
> region sample factora factorb
> factorc
> 0.1 10 0.895 0.903 0.378
> 0.2 10 0.811 0.865 0.688
> 0.1 20 0.735 0.966 0.611
> 0.2 20 0.777 0.732 0.653
> 0.1 30 0.600 0.778 0.694
> 0.2 30 0.466 174.592 0.461
> 0.1 40 0.446 0.432 0.693
> 0.2 40 0.392 0.294 0.686
>
> The first column should be the independent variable, the second should
> compute a bold line for sample(10) and dash line for sample 20.
>
> What about the other two values of “sample”?
>
> The others variables are outcomes for each of the first scenarios, and
> so it should: the 3rd, 4th and 5th columns should be blue, red and
> green respectively.
>
> Resume :)
>
> I should have a graph, in the x-axe should have the region and in the
> y axe, the factor.
> Lines:
> 1 - blue and bold for region 0.1, sample 10 and factor a
> 2 - blue and dash for region 0.2, sample 10 and factor a
> 3 - red and bold for region 0.1, sample 10 and factor b
> 4 - red and dash for region 0.2, sample 10 and factor b
> 5 - green and bold for region 0.1, sample 10 and factor c
> 6 - green and dash for region 0.2, sample 10 and factor c
>
> Not consistent with what you said above. These are no longer lines, but
> points.
>
> nonetheless the independent variable is nominal, I should plot a line
> graph.
>
> Can anyone help me please?
> I have my file as a cvs file, so I first read that file (that I know
> how to do :)).
>
> But I have it in that format.
>
> Best,
> RO
>
> Atenciosamente,
> Rosa Oliveira
>
> --
> ____________________________________________________________________________
>
> Rosa Celeste dos Santos Oliveira,
>
> E-mail: rosita21 at gmail.com <mailto:rosita21 at gmail.com>
> Tlm: +351 939355143
> Linkedin: https://pt.linkedin.com/in/rosacsoliveira [https://pt.linkedin.com/in/rosacsoliveira]
> <https://pt.linkedin.com/in/rosacsoliveira [https://pt.linkedin.com/in/rosacsoliveira]>
> ____________________________________________________________________________
> "Many admire, few know"
> Hippocrates
>
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>
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