[R] compute values by condition in DF by rownames
Karim Mezhoud
kmezhoud at gmail.com
Tue Feb 17 09:10:24 CET 2015
Thanks JS
I think aggregate function is better.
Karim
Le 17 févr. 2015 08:33, "JS Huang" <js.huang at protective.com> a écrit :
> Hi,
>
> I hope that someone can provide a better way to implement it. This is my
> implementation.
>
> > data
> X2 gbm_tcga lusc_tcga ucec_tcga_pub
> 1 gbm_tcga 1.000000000 0.14053719 -0.102847164
> 2 gbm_tcga 1.000000000 0.04413434 0.013568055
> 3 gbm_tcga 1.000000000 -0.20003971 0.038971817
> 4 gbm_tcga 1.000000000 0.14569916 0.009947045
> 5 lusc_tcga 0.140537191 1.00000000 0.133080708
> 6 lusc_tcga 0.044134345 1.00000000 0.062024713
> 7 lusc_tcga -0.200039712 1.00000000 -0.130239551
> 8 lusc_tcga 0.145699156 1.00000000 0.041796670
> 9 ucec_tcga_pub -0.102847164 0.13308071 1.000000000
> 10 ucec_tcga_pub 0.013568055 0.06202471 1.000000000
> 11 ucec_tcga_pub 0.038971817 -0.13023955 1.000000000
> 12 ucec_tcga_pub 0.009947045 0.04179667 1.000000000
> > test
> function(x)
> {
> tempMatrix <- matrix(0,nrow=3,ncol=3)
> lev <- levels(x$X2)
> for (i in 1:length(lev))
> {
> tempMatrix[i,1] = sum(ifelse(abs(x[x$X2==lev[i],2])>0.2,1,0))
> tempMatrix[i,2] = sum(ifelse(abs(x[x$X2==lev[i],3])>0.2,1,0))
> tempMatrix[i,3] = sum(ifelse(abs(x[x$X2==lev[i],4])>0.2,1,0))
> }
> result <- data.frame(lev,tempMatrix)
> names(result) <- c("X2","gbm_tcga","lusc_tcga","tcga_pub")
> return(result)
> }
> > test(data)
> X2 gbm_tcga lusc_tcga tcga_pub
> 1 gbm_tcga 4 1 0
> 2 lusc_tcga 1 4 0
> 3 ucec_tcga_pub 0 0 4
> >
>
>
>
> --
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> Sent from the R help mailing list archive at Nabble.com.
>
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