[R] F Distribution

[peter dalgaard]

qf() (as you might have figured from the help page for pf()....)

-pd 

> On 21 Dec 2015, at 20:51 , Robert Sherry <rsherry8 at comcast.net> wrote:
> 
> 
> When I use a table, from a Schaum book, I see that for the 95 percentile, with v_1 = 1 and v_2 = 1 the value is 161. In the modern era,
> looking values up in a table is less than ideal. Therefore, I would expect R to have a function to do this and based upon my
> reading of the documentation, I would expect the following call to get the value I expect:
>     pf( .95,1, 1)
> However, it produces
>    0.4918373
> Therefore, I conclude that I am using the wrong function. What function should I use?
> 
> Thanks
> Bob
> 
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-- 
Peter Dalgaard, Professor,
Center for Statistics, Copenhagen Business School
Solbjerg Plads 3, 2000 Frederiksberg, Denmark
Phone: (+45)38153501
Office: A 4.23
Email: pd.mes at cbs.dk  Priv: PDalgd at gmail.com