[R] testing whether two character vectors contain (the same) items in the same order

Robert Baer rbaer at atsu.edu
Sat Aug 8 20:21:49 CEST 2015


And I probably should have included this link:
http://journal.r-project.org/archive/2014-1/loo.pdf

On 8/8/2015 12:50 PM, Robert Baer wrote:
>
>
> On 8/6/2015 5:25 AM, Federico Calboli wrote:
>> Hi All,
>>
>> let’s assume I have a vector of letters drawn only once from the 
>> alphabet:
>>
>> x = sample(letters, 15, replace = F)
>> x
>>   [1] "z" "t" "g" "l" "u" "d" "w" "x" "a" "q" "k" "j" "f" "n" “v"
>>
>> y = x[c(1:7,9:8, 10:12, 14, 15, 13)]
>>
>> I would now like to test how good a match y is for x.  Obviously I 
>> can transform the letters in numbers and use a rank test, but I was 
>> left wondering whether this is the only solution and whether there 
>> are more appropriate solutions that are already implemented in R (I 
>> am not going to reinvent the wheel if I can avoid it).
>>
>> BW
>>
>> F
> Perhaps
> install.packages("stringdist")
> help(package = 'stringdist')
>
>
>
>
>
>>
>> -- 
>> Federico Calboli
>> Ecological Genetics Research Unit
>> Department of Biosciences
>> PO Box 65 (Biocenter 3, Viikinkaari 1)
>> FIN-00014 University of Helsinki
>> Finland
>>
>> federico.calboli at helsinki.fi
>>
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>



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