[R] testing whether two character vectors contain (the same) items in the same order

[Bert Gunter]

Define "goodness of match" .  For exact matches, see ?"==" , all.equal, etc.

Bert

On Thursday, August 6, 2015, Federico Calboli <federico.calboli at helsinki.fi>
wrote:

> Hi All,
>
> let’s assume I have a vector of letters drawn only once from the alphabet:
>
> x = sample(letters, 15, replace = F)
> x
>  [1] "z" "t" "g" "l" "u" "d" "w" "x" "a" "q" "k" "j" "f" "n" “v"
>
> y = x[c(1:7,9:8, 10:12, 14, 15, 13)]
>
> I would now like to test how good a match y is for x.  Obviously I can
> transform the letters in numbers and use a rank test, but I was left
> wondering whether this is the only solution and whether there are more
> appropriate solutions that are already implemented in R (I am not going to
> reinvent the wheel if I can avoid it).
>
> BW
>
> F
>
>
> --
> Federico Calboli
> Ecological Genetics Research Unit
> Department of Biosciences
> PO Box 65 (Biocenter 3, Viikinkaari 1)
> FIN-00014 University of Helsinki
> Finland
>
> federico.calboli at helsinki.fi <javascript:;>
>
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-- 
Bert Gunter

"Data is not information. Information is not knowledge. And knowledge is
certainly not wisdom."
   -- Clifford Stoll

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