[R] Question on funcion and npar

Marc Schwartz marc_schwartz at me.com
Tue Apr 21 20:13:13 CEST 2015


> On Apr 21, 2015, at 1:05 PM, Luciano La Sala <lucianolasala at yahoo.com.ar> wrote:
> 
> Dear everyone,
> 
> The following function, taken from Quick-R, gets measures of central tendency and spread for a numeric vector x.
> 
> I can't figure out what the argument npar means in each instance.
> Any tips will be most appreciated.
> 
> mysummary <- function(x, npar=TRUE, print=TRUE) {
>  if (!npar) {
>    center <- mean(x); spread <- sd(x)
>  } else {
>    center <- median(x); spread <- mad(x)
>  }
>  if (print & !npar) {
>    cat("Mean=", center, "\n", "SD=", spread, "\n")
>  } else if (print & npar) {
>    cat("Median=", center, "\n", "MAD=", spread, "\n")
>  }
>  result <- list(center=center,spread=spread)
>  return(result)
> }
> 


Presumably ‘nonparametric’, since median()/mad() is used in lieu of mean()/sd(), if npar = TRUE.

Regards,

Marc Schwartz



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