[R] sort adjacency matrix

[David L Carlson]

The answer depends on what kind of matrix/data frame you have. That is why we encourage people to use dput() to create a copy of the sample data in their email. Some combination of order() function the rowSums() function will probably get you what you want. For example,

dat[order(rowSums(dat=="1"), decreasing=TRUE),]

or

dat[order(rowSums(dat), decreasing=TRUE),]

or

dat[order(rowSums(dat, na.rm=TRUE), decreasing=TRUE),]

Note that the order is not unique since there are ties in the number of 1s.

-------------------------------------
David L Carlson
Department of Anthropology
Texas A&M University
College Station, TX 77840-4352


-----Original Message-----
From: R-help [mailto:r-help-bounces at r-project.org] On Behalf Of Ragia Ibrahim
Sent: Monday, April 6, 2015 12:18 PM
To: r-help at r-project.org
Subject: [R] sort adjacency matrix

Dear group 
i have the following matrix

1  . . 1 . . 1 . . . .
2  . . . . . . 1 . . .
3  1 . . . 1 . . 1 . 1
4  . . . . . 1 . . . .
5  . . 1 . . . . . . 1
6  1 . . 1 . . . . 1 .
7  . 1 . . . . . 1 . .
8  . . 1 . . . 1 . . 1
9  . . . . . 1 . . . 1
10 . . 1 . 1 . . 1 1 .

I want to sort it according to ones in each row ascending (where max number of ones first)

to be as follow

3  1 . . . 1 . . 1 . 1
10 . . 1 . 1 . . 1 1 .
6  1 . . 1 . . . . 1 .8  . . 1 . . . 1 . . 11  . . 1 . . 1 . . . .5  . . 1 . . . . . . 17  . 1 . . . . . 1 . .9  . . . . . 1 . . . 12  . . . . . . 1 . . .4  . . . . . 1 . . . .

how can I do this in R
thanks in advance
 		 	   		  
	[[alternative HTML version deleted]]

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