[R] if else statement in loop

PIKAL Petr petr.pikal at precheza.cz
Mon Sep 29 08:39:17 CEST 2014


Hi

Please, be more clear in what do you want. I get many errors trying your code and your explanation does not help much.

> for(i in length(1:(2*nrow(X)))){
+     Y$IID1new <- ifelse((as.character(Y[,2]) == as.characterXl[,i]) & X$IID1new != '') , as.character(as.matrix(X[,(2*nrow(X)+i)])),'')
Error: unexpected ',' in:
"for(i in length(1:(2*nrow(X)))){
    Y$IID1new <- ifelse((as.character(Y[,2]) == as.characterXl[,i]) & X$IID1new != '') ,"
> }
Error: unexpected '}' in "}"
> for(i in length(1:(2*nrow(X)))){
+     Y$IID1new <- ifelse((as.character(Y[,2]) == as.characterXl[,i]) &
+ X$IID1new != '') , as.character(as.matrix(X[,(2*nrow(X)+i)])),'')
Error: unexpected ',' in:
"    Y$IID1new <- ifelse((as.character(Y[,2]) == as.characterXl[,i]) &
X$IID1new != '') ,"
> }


Beside, this column X$IID1new != '' does not exist in X

Here you clearly ask for nonexistent column, and why the heck you want to select column by number of rows?

> as.character(as.matrix(X[,(2*nrow(X)+1)]))
Error in `[.data.frame`(X, , (2 * nrow(X) + 1)) :
  undefined columns selected

So based on your toy data frames, what shall be the result after your computation.

Regards
Petr


> -----Original Message-----
> From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-
> project.org] On Behalf Of Kate Ignatius
> Sent: Sunday, September 28, 2014 9:14 PM
> To: r-help
> Subject: [R] if else statement in loop
>
> I have two data frames
>
> For simplicity:
>
> X=
>
> V1 V2 V3  V4 V5 V6
> samas4 samas5 samas6 samas4_father samas5_mother samas6_sibling
> samas4 samas5 samas6 samas4_father samas5_mother samas6_sibling
> samas4 samas5 samas6 samas4_father samas5_mother samas6_sibling
>
> Y=
>
> FID IID
> FAM01 samas4
> FAM01 samas5
> FAM01 samas6
>
> I want to set to create a new IID in Y using V4 V5 V6 in X using an
> ifelse statement in a loop.  I've used something like the following
> (after figuring out my factor problem):
>
> for(i in length(1:(2*nrow(X)))){
>     Y$IID1new <- ifelse((as.character(Y[,2]) == as.characterXl[,i]) &
> X$IID1new != '') , as.character(as.matrix(X[,(2*nrow(X)+i)])),'')
> }
>
> But of course this tends to overwrite.
>
> Is there an easy way to set up a loop to replace missing values? This
> didn't work either but not sure if its as easy as this:
>
> Y$IID1new <- ifelse((as.character(Y[,2]) == as.characterXl[,i]) &
> X$IID1new != '') , as.character(as.matrix(X[,(2*nrow(X)+i)])),'')
>
> for(i in length(2:(2*nrow(X)))){
> ifelse((as.character(Y[,i]) == as.character(Xl[,i])),
> X[is.na(X$IID1new)] <- as.character(as.matrix(X[(2*nrow(X)+i)])),'')
> }
>
> Thanks!
>
> K.
>
> ______________________________________________
> R-help at r-project.org mailing list
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> PLEASE do read the posting guide http://www.R-project.org/posting-
> guide.html
> and provide commented, minimal, self-contained, reproducible code.

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