[R] SOLVED: evaluate NA to FALSE instead of NA?

[Rainer M Krug]

Thanks Joshua and Sven - I completely forgot about which() .

Pascal - I never new about complete.cases - interesting function.

Thanks,

Rainer
 

Rainer M Krug <Rainer at krugs.de> writes:

> Hi
>
> I want to evaluate NA and NaN to FALSE (for indexing) so I would like to
> have the result as indicated here:
>
> ,----
> | > p <- c(1:10/100, NA, NaN)
> | > p
> |  [1] 0.01 0.02 0.03 0.04 0.05 0.06 0.07 0.08 0.09 0.10   NA  NaN
> | > p[p<=0.05]
> | [1] 0.01 0.02 0.03 0.04 0.05   NA   NA
> | > p[sapply(p<=0.05, isTRUE)]
> | [1] 0.01 0.02 0.03 0.04 0.05  <<<=== I want this
> `----
>
> Is there a way that I can do this more easily then in my example above?
> It works, but it strikes me that there is not a better way of doing
> this - am I missing a command or option?
>
> Thanks,
>
> Rainer

-- 
Rainer M. Krug
email: Rainer<at>krugs<dot>de
PGP: 0x0F52F982
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