[R] create new rows with 0, if nessecary

Martyn Byng martyn.byng at nag.co.uk
Fri May 16 13:50:36 CEST 2014


Hi,

Something like:

aa <-structure(list(Cat = c(101, 103), Hours = c(15, 10)), .Names = c("Cat","Hours"), row.names = c(NA, -2L), class = "data.frame")
bb <-structure(list(Cat = c(103, 106), Hours = c(16, 11)), .Names = c("Cat","Hours"), row.names = c(NA, -2L), class = "data.frame")
dd <- data.frame(Cat=min(aa[,1],bb[,1]):max(aa[,1],bb[,1]))

gg1 <- merge(aa,dd,all=TRUE)
gg1[is.na(gg1[,2]),2] <- 0

gg2 <- merge(bb,dd,all=TRUE)
gg2[is.na(gg2[,2]),2] <- 0

Might be what you are looking for.

Martyn
-----Original Message-----
From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org] On Behalf Of Mat
Sent: 16 May 2014 12:18
To: r-help at r-project.org
Subject: [R] create new rows with 0, if nessecary

hello togehter, 

i have a little problem, i have frames like this two:
      Cat      Hours      
A    101     15
B    103     10

      Cat      Hours      
A    103     16
B    106     11

I need to convert this 2 data.frames into the following equal structure:
      Cat      Hours
A    101
B    102
C    103
D    104
E    105
F    106

The 2 examples should be look this one:

      Cat      Hours
A    101      15
B    102       0
C    103      10
D    104       0
E    105       0
F    106       0

      Cat      Hours
A    101       0
B    102       0
C    103      16
D    104       0
E    105       0
F    106      11



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