[R] Problem with do.call().
Rolf Turner
r.turner at auckland.ac.nz
Fri Mar 28 00:17:58 CET 2014
I was under the impression that
do.call(foo,list(x=x,y=y))
should yield the same result as
foo(x,y).
However if I do
x <- 1:10
y <- (x-5.5)^2
do.call(plot,list(x=x,y=y))
I get the expected plot but with the y-values (surrounded by c()) being
printed (vertically) in the left-hand margin of the plot.
The help for do.call() says:
> The behavior of some functions, such as substitute, will not be the
> same for functions evaluated using do.call as if they were evaluated
> from the interpreter. The precise semantics are currently undefined and
> subject to change.
Am I being bitten by an instance of this phenomenon? Seems strange.
I would be grateful for enlightenment.
cheers,
Rolf Turner
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