[R] Help with prob in sample()
Thomas
thomas.chesney at nottingham.ac.uk
Fri Mar 7 11:24:12 CET 2014
I'm trying to figure out exactly what the prob parameter in the sample
function does.
With the following code, does sample look randomly for the first
possible sample--let's say it choses the second element--and then
assess whether it can be chosen according to it's probability which is
0.8? It seems unlikely it would work like this.
Or does it create a `biased die' which in this case would have ten
sides that each come up according to the probabilities in myProb, and
roll it to see which is the first element chosen, then remove that
element, create a new biased die with 9 sides and roll it again?
i <- c(1:10)
myProbs <- c(0.2, 0.8, 0.3, 0.2, 0.1, 0.1, 0.1, 0.2, 0.3, 0.4)
f <- sample(i,5, replace=FALSE, prob=myProbs)
Then what's the difference in terms of sampling between the following
two examples, the second of which has been created so that the
probabilities add to 1?
i <- c(1:10)
myProbs <- c(0.1, 0.1, 0.1, 0.1, 0.1, 0.9, 0.9, 0.9, 0.9, 0.9)
f <- sample(i,5, replace=FALSE, prob=myProbs)
i <- c(1:10)
myProbs <- c(0.1/5, 0.1/5, 0.1/5, 0.1/5, 0.1/5, 0.9/5, 0.9/5, 0.9/5,
0.9/5, 0.9/5)
f <- sample(i,5, replace=FALSE, prob=myProbs)
Thank you,
Thomas Chesney
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