[R] data frame manipulation
Jeff Newmiller
jdnewmil at dcn.davis.ca.us
Thu Feb 20 22:24:28 CET 2014
Depending what you really want to achieve, the following may be useful or
educational:
dat$ID2x <- with( dat, ave( rep( 1, nrow( dat ) ), ID, USE, FUN=cumsum ) )
dat$ID2y <- dat$ID2x
dat$ID2y[ dat$USE != "001" ] <- NA
On Thu, 20 Feb 2014, arun wrote:
> Hi,
> Try:
> dat$ID2 <- with(dat,ave(seq_along(USE),ID,FUN=function(x){x1 <- USE[x] =='001'; ifelse(!x1,'',cumsum(x1))}))
> A.K.
>
>
>
>
> On Thursday, February 20, 2014 3:31 PM, Pedro Mardones <mardones.p at gmail.com> wrote:
> Dear R community;
>
> I'm kind of stuck with the following situation and would appreciate any
> hint. Let's assume I have the following data frame:
>
> dat <- data.frame(ID = c(rep("01",18), rep("02",16)), USE = c(c("001","004",
> "005","007","001","004","005","007","012","001","004","005","007","001","004",
> "005","007","012"),c("004","005","007","013","001","004","005","007","001","004",
> "005","007","001","004","005","007")),ID2 = "")
>
> What I would like to achieve is to number all the "001" occurrences in USE
> for each ID individually and store them in ID2. In other words, something
> like this:
>
> ID USE ID2
> 1 01 001 1
> 2 01 004
> 3 01 005
> 4 01 007
> 5 01 001 2
> 6 01 004
> 7 01 005
> 8 01 007
> 9 01 012
> 10 01 001 3
> 11 01 004
> 12 01 005
> 13 01 007
> 14 01 001 4
> 15 01 004
> 16 01 005
> 17 01 007
> 18 01 012
> 19 02 004
> 20 02 005
> 21 02 007
> 22 02 013
> 23 02 001 1
> 24 02 004
> 25 02 005
> 26 02 007
> 27 02 001 2
> 28 02 004
> 29 02 005
> 30 02 007
> 31 02 001 3
> 32 02 004
> 33 02 005
> 34 02 007
>
> Thanks again,
> Pedro
>
> [[alternative HTML version deleted]]
>
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> and provide commented, minimal, self-contained, reproducible code.
>
>
> ______________________________________________
> R-help at r-project.org mailing list
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> PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
> and provide commented, minimal, self-contained, reproducible code.
>
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