[R] grep for multiple pattern?
Rainer M Krug
Rainer at krugs.de
Thu Feb 13 17:25:02 CET 2014
On 02/13/14, 17:23 , jim holtman wrote:
> use the "|" in regular expressions:
>
> grep(c("an|em|eb", month.name <http://month.name/>)
Thanks - again a reason to learn regexp.
Cheers,
Rainer
>
>
> Jim Holtman
> Data Munger Guru
>
> What is the problem that you are trying to solve?
> Tell me what you want to do, not how you want to do it.
>
>
> On Thu, Feb 13, 2014 at 9:43 AM, Rainer M Krug <Rainer at krugs.de
> <mailto:Rainer at krugs.de>> wrote:
>
> Hi
>
> I want to search for multiple pattern as grep is doing for a single
> pattern, but this obviously not work:
>
> > grep("an", month.name <http://month.name>)
> [1] 1
> > grep("em", month.name <http://month.name>)
> [1] 9 11 12
> > grep("eb", month.name <http://month.name>)
> [1] 2
> > grep(c("an", "em", "eb"), month.name <http://month.name>)
> [1] 1
> Warning message:
> In grep(c("an", "em", "eb"), month.name <http://month.name>) :
> argument 'pattern' has length > 1 and only the first element will
> be used
> >
>
> Is there an equivalent which returns the positions as grep is doing, but
> not using the strict full-string matching of match()?
>
> I could obviously do:
>
> > unlist( sapply(pat, grep, month.name <http://month.name> ) )
> an em1 em2 em3 eb
> 1 9 11 12 2
>
> but is there a more compact command I am missing?
>
> Thanks,
>
> Rainer
>
> --
> Rainer M. Krug, PhD (Conservation Ecology, SUN), MSc (Conservation
> Biology, UCT), Dipl. Phys. (Germany)
>
> Centre of Excellence for Invasion Biology
> Stellenbosch University
> South Africa
>
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>
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>
>
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--
Rainer M. Krug, PhD (Conservation Ecology, SUN), MSc (Conservation
Biology, UCT), Dipl. Phys. (Germany)
Centre of Excellence for Invasion Biology
Stellenbosch University
South Africa
Tel : +33 - (0)9 53 10 27 44
Cell: +33 - (0)6 85 62 59 98
Fax : +33 - (0)9 58 10 27 44
Fax (D): +49 - (0)3 21 21 25 22 44
email: Rainer at krugs.de
Skype: RMkrug
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