[R] how can i count appearence of zero?
arun
smartpink111 at yahoo.com
Tue Feb 11 08:56:13 CET 2014
Hi,
Try
dat1<- as.matrix(read.table(text="V1 V2 V3 V4 V5 V6 V7 V8 V9 V10 V11
6 6 6 6 6 0 0 0 0 0 0
5 5 5 5 5 5 5 5 5 5 5
1 0 0 0 0 0 0 0 0 0 0
5 5 5 0 0 0 0 0 0 0 0
6 8 11 0 9 0 0 0 0 0 0
2 0 0 2 0 0 0 0 0 2 2",header=TRUE))
lst1 <- apply(!dat1,1,function(x) {r1 <- rle(x);r1$lengths[r1$values]})
mLen <- max(sapply(lst1,length))
res <- cbind(dat1,t(sapply(lst1,function(x) c(x,rep(NA,mLen-length(x))))))
colnames(res)[colnames(res)==""] <- paste0("Sum",seq(sum(colnames(res)=="")))
res
A.K.
Hi All,
If you could help me with this problem I would greatly appreciate it.
Suppose I have a matrix X
V1 V2 V3 V4 V5 V6 V7 V8 V9 V10 V11
[1,] 6 6 6 6 6 0 0 0 0 0 0
[2,] 5 5 5 5 5 5 5 5 5 5 5
[3,] 1 0 0 0 0 0 0 0 0 0 0
[4,] 5 5 5 0 0 0 0 0 0 0 0
[5,] 6 8 11 0 9 0 0 0 0 0 0
[6,] 2 0 0 2 0 0 0 0 0 2 2
I would like to sum the number of times a 0 appears. So what I would like is to have
Sum
[1,] 6 6 6 6 6 0 0 0 0 0 0 6 NA
[2,] 5 5 5 5 5 5 5 5 5 5 5 NA NA
[3,] 1 0 0 0 0 0 0 0 0 0 0 10 NA
[4,] 5 5 5 0 0 0 0 0 0 0 0 8 NA
[5,] 6 8 11 0 9 0 0 0 0 0 0 1 6
[6,] 2 0 0 2 0 0 0 0 0 2 2 2 5
Thanks in advance.
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