[R] data.table/ifelse conditional new variable question
Kate Ignatius
kate.ignatius at gmail.com
Sun Aug 17 02:58:47 CEST 2014
Actually - I didn't check this before, but these are not all nuclear
families (as I assumed they were). That is, some don't have a father
or don't have a mother.... Usually if this is the case PID or MID will
become 0, respectively, for the child. How can the code be edit to
account for this?
On Sat, Aug 16, 2014 at 8:02 PM, Kate Ignatius <kate.ignatius at gmail.com> wrote:
> Thanks!
>
> I think I know what is being done here but not sure how to fix the
> following error:
>
> Error in l$PID[l$\Relationship == "sibling"] <- l$Sample.ID[father] :
> replacement has length zero
>
>
>
> On Sat, Aug 16, 2014 at 6:48 PM, Jorge I Velez <jorgeivanvelez at gmail.com> wrote:
>> Dear Kate,
>>
>> Assuming you have nuclear families, one option would be:
>>
>> x <- read.table(textConnection("Family.ID Sample.ID Relationship
>> 14 62 sibling
>> 14 94 father
>> 14 63 sibling
>> 14 59 mother
>> 17 6004 father
>> 17 6003 mother
>> 17 6005 sibling
>> 17 368 sibling
>> 130 202 mother
>> 130 203 father
>> 130 204 sibling
>> 130 205 sibling
>> 130 206 sibling
>> 222 9 mother
>> 222 45 sibling
>> 222 34 sibling
>> 222 10 sibling
>> 222 11 sibling
>> 222 18 father"), header = TRUE)
>> closeAllConnections()
>>
>> xs <- with(x, split(x, Family.ID))
>> res <- do.call(rbind, lapply(xs, function(l){
>> l$PID <- l$MID <- 0
>> father <- with(l, Relationship == 'father')
>> mother <- with(l, Relationship == 'mother')
>> l$PID[l$Relationship == 'sibling'] <- l$Sample.ID[father]
>> l$MID[l$Relationship == 'sibling'] <- l$Sample.ID[mother]
>> l
>> }))
>> res
>>
>> HTH,
>> Jorge.-
>>
>>
>> Best regards,
>> Jorge.-
>>
>>
>>
>> On Sun, Aug 17, 2014 at 5:42 AM, Kate Ignatius <kate.ignatius at gmail.com>
>> wrote:
>>>
>>> Hi,
>>>
>>> I have a data.table question (as well as if else statement query).
>>>
>>> I have a large list of families (file has 935 individuals that are
>>> sorted by famiy of varying sizes). At the moment the file has the
>>> columns:
>>>
>>> SampleID FamilyID Relationship
>>>
>>> To prevent from having to make a pedigree file by hand - ie adding a
>>> PaternalID and a MaternalID one by one I want to try write a script
>>> that will quickly do this for me (I eventually want to run this
>>> through a program such as plink) Is there a way to use data.table
>>> (maybe in conjucntion with ifelse to do this effectively)?
>>>
>>> An example of the file is something like:
>>>
>>> Family.ID Sample.ID Relationship
>>> 14 62 sibling
>>> 14 94 father
>>> 14 63 sibling
>>> 14 59 mother
>>> 17 6004 father
>>> 17 6003 mother
>>> 17 6005 sibling
>>> 17 368 sibling
>>> 130 202 mother
>>> 130 203 father
>>> 130 204 sibling
>>> 130 205 sibling
>>> 130 206 sibling
>>> 222 9 mother
>>> 222 45 sibling
>>> 222 34 sibling
>>> 222 10 sibling
>>> 222 11 sibling
>>> 222 18 father
>>>
>>> But the goal is to have a file like this:
>>>
>>> Family.ID Sample.ID Relationship PID MID
>>> 14 62 sibling 94 59
>>> 14 94 father 0 0
>>> 14 63 sibling 94 59
>>> 14 59 mother 0 0
>>> 17 6004 father 0 0
>>> 17 6003 mother 0 0
>>> 17 6005 sibling 6004 6003
>>> 17 368 sibling 6004 6003
>>> 130 202 mother 0 0
>>> 130 203 father 0 0
>>> 130 204 sibling 203 202
>>> 130 205 sibling 203 202
>>> 130 206 sibling 203 202
>>> 222 9 mother 0 0
>>> 222 45 sibling 18 9
>>> 222 34 sibling 18 9
>>> 222 10 sibling 18 9
>>> 222 11 sibling 18 9
>>> 222 18 father 0 0
>>>
>>> I've tried searches for this but with no luck. Greatly appreciate any
>>> help - even if its just a link to a great example/solution!
>>>
>>> Thanks!
>>>
>>> ______________________________________________
>>> R-help at r-project.org mailing list
>>> https://stat.ethz.ch/mailman/listinfo/r-help
>>> PLEASE do read the posting guide
>>> http://www.R-project.org/posting-guide.html
>>> and provide commented, minimal, self-contained, reproducible code.
>>
>>
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