[R] List of Dataframes

arun smartpink111 at yahoo.com
Tue Apr 22 03:01:27 CEST 2014


Hi,
#or you could use:
do.call(rbind,result)


A.K.


On Monday, April 21, 2014 4:48 PM, Timothy W. Cook <tim at mlhim.org> wrote:
Okay, all day on this and I send the msg. and almost immediately discover
that:

dat <- ldply(result)

solves the problem.




On Mon, Apr 21, 2014 at 5:40 PM, Timothy W. Cook <tim at mlhim.org> wrote:

> I am processing an arbitrary number of XML files and extracting specific
> nodes.  I then create a dataframe for each nodeset.
> I return a list containing these dataframes.
>
> Example:
>
> > str(result)List of 2
>  $ :'data.frame':    1 obs. of  5 variables:
>   ..$ data-name       : chr "Etiologic diagnosis of Acute Febrile Hemorrhagic Syndrome"
>   ..$ valid-time-begin: chr "2014-04-28T01:31:49Z"
>   ..$ valid-time-end  : chr "3014-04-28T01:31:48Z"
>   ..$ DvString-dv     : chr "Typhoid fever"
>   ..$ language        : chr "en-US"
>  $ :'data.frame':    1 obs. of  5 variables:
>   ..$ data-name       : chr "Etiologic diagnosis of Acute Febrile Hemorrhagic Syndrome"
>   ..$ valid-time-begin: chr "2014-04-29T01:02:00Z"
>   ..$ valid-time-end  : chr "3014-04-29T01:01:59Z"
>   ..$ DvString-dv     : chr "Dengue"
>   ..$ language        : chr "en-US"
>
>
> I would like to have each of the list items as a row in one dataframe.  My
> attempts so far have been unsuccessful. I have tried t(), merge(),
> lapply(), etc.  Short of some elaborate *for loop* (I know is frowned
> upon)  I am out of answers.
>
> I would think this is a fairly common need, maybe even a FAQ that I
> haven't found yet.
>
> Thanks in advance.
>
>
>
>
>
>
>
> --
>
> ============================================
> Timothy Cook
> LinkedIn Profile:http://www.linkedin.com/in/timothywaynecook
> MLHIM http://www.mlhim.org
>
>


-- 

============================================
Timothy Cook
LinkedIn Profile:http://www.linkedin.com/in/timothywaynecook
MLHIM http://www.mlhim.org

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