[R] how to find interval?

Berend Hasselman bhh at xs4all.nl
Tue Sep 17 12:58:19 CEST 2013


On 17-09-2013, at 12:41, Berend Hasselman <bhh at xs4all.nl> wrote:

> 
> On 17-09-2013, at 12:15, gildororonar at mail-on.us wrote:
> 
>> I can do this:
>> 
>>> 1:10 %in% c(3, 5, 6, 10)
>> [1] FALSE FALSE  TRUE FALSE  TRUE  TRUE FALSE FALSE FALSE  TRUE
>> 
>> but what I wish to get is:
>> 
>> [1] 3 2 1 4
>> 
>> let me explain:
>> 
>> 3 # [1:3] ends with TRUE, i.e. FALSE FALSE  TRUE
>> 2 # [4:5] ends with TRUE, i.e. FALSE  TRUE
>> 1 # [6:6] ends with TRUE, i.e. TRUE
>> 4 # [7:10] ends with TRUE, i.e. FALSE FALSE FALSE TRUE
>> 
>> That is, %in% gave me a serial whether or not the element is in a set, the length is equal to the former, i.e. 1:10
>> 
>> But I wish to get a serial of intevals of occurance of the element in the set, the length is equal to the latter i.e. c(3, 5, 6, 10)
> 
> One way is
> 
>> diff(c(0,which(1:10 %in% a)))
> [1] 3 2 1 4
> 

and of course a equals c(3, 5, 6, 10) !

Berend



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