[R] using a variable for a column name in a formula

[p_connolly]

On 2013-10-14 10:04, David Epstein wrote:
> lm(height ~ ., data=X)
> works fine.
> 
> However
> nnn <- "height" ;  lm(nnn ~ . ,data=X)
> fails
> 
> How do I write such a formula, which depends on the value of a string
> variable like nnn above?

as.formula() with paste() could work, but from where you are now, try
lm(get(nnn) ~ . ,data=X)


HTH

> 
> A typical application might be a program that takes a data frame
> containing only numerical data, and figures out which of the columns
> can be best predicted from all the other columns.
> 
> Thanks
> David
> 
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