[R] storing element number of a list in a column data frame
Sarah Goslee
sarah.goslee at gmail.com
Thu Oct 3 16:58:07 CEST 2013
Hi,
Something like this, maybe:
> mytest.df <- data.frame(i=seq_along(mytest)[!sapply(mytest, is.null)], n=unlist(mytest))
> mytest.df
i n
1 1 45
2 3 18
3 5 99
It took me a couple of tries, because I wasn't expecting unlist() to
drop the NULL values:
> unlist(mytest)
[1] 45 18 99
Sarah
On Thu, Oct 3, 2013 at 10:41 AM, Massimo Bressan
<mbressan at arpa.veneto.it> wrote:
> #let's suppose I have a list like this
>
> mytest<-list(45, NULL, 18, NULL, 99)
>
> #to note that this is just an amended example because in fact
>
> #I'm dealing with a long list (more than 400 elements)
>
> #with no evident pattern of the NULL values
>
> #I want to end up with a data frame like the following
>
> data.frame(i=c(1,3,5), n=c(45,18,99))
>
> #i.e. a data frame storing in
>
> #column i the number of corresponding element list
>
> #column n the unique component of that element
>
> #I've been trying with
>
> do.call(rbind, mytest)
>
> #or
>
> do.call(rbind.data.frame, mytest)
>
> #but this approach is not properly achieving the desired result
>
> #now I'm in trouble on how to store each element number of the list in
> the first column data frame
>
> #any help for this?
>
> #thanks
>
>
> [[alternative HTML version deleted]]
>
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--
Sarah Goslee
http://www.functionaldiversity.org
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