[R] quotation marks and scan
MacQueen, Don
macqueen1 at llnl.gov
Mon Nov 18 17:38:15 CET 2013
I know you have a solution, but I would have suggested using print() with
quote=FALSE as a better way to illuminate what is going on, as in this
example:
> foo <- 'bah"bah'
> foo
[1] "bah\"bah"
> print(foo)
[1] "bah\"bah"
> print(foo, quote=FALSE)
[1] bah"bah
As others said, the backslash isn't really there. So you only have to get
rid of the " which you can do with
> gsub('"','',foo)
[1] "bahbah"
To summarize, in R, due to its rules for formatting printed output, what
you see isn't always exactly what you have, and this is an example.
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
On 11/17/13 2:07 PM, "Erin Hodgess" <erinm.hodgess at gmail.com> wrote:
>Dear R People:
>
>I'm sure that this is a very simple problem, but I have been wresting with
>it for some time.
>
>I have the following file that has the following one line:
>
> CRS("+init=epsg:28992")
>
>Fair enough. I scan it into R and get the following:
>
>> u
>[1] "CRS(\"+init=epsg:28992\")"
>> gsub(pattern='\"',replacement='"',x=u)
>[1] "CRS(\"+init=epsg:28992\")"
>
>I need to get rid of the extra quotation marks and slashes. I've tried
>all
>sorts of things, including gsub, as you see, but no good.
>
>Thank you for any help.
>
>Sincerely,
>Erin
>
>
>--
>Erin Hodgess
>Associate Professor
>Department of Computer and Mathematical Sciences
>University of Houston - Downtown
>mailto: erinm.hodgess at gmail.com
>
> [[alternative HTML version deleted]]
>
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