[R] Extract values from vector and repeat by group
arun
smartpink111 at yahoo.com
Mon Nov 18 15:42:05 CET 2013
Hi,
I would also add an index to make it work for groups that doesn't have time=4.
df1 <- df[-12,]
fun1 <- function(dat,n) {
indx <- with(dat,tapply(time==n,group,FUN=any))
indx2 <- with(dat,ave(time==n,group,FUN=any))
dat[indx2,"new"] <- rep(dat$var[dat$time==n],rle(dat$group)$lengths[indx])
dat[!is.na(dat$new),]
}
fun1(df,4)
fun1(df1,4)
A.K.
On Monday, November 18, 2013 9:18 AM, PIKAL Petr <petr.pikal at precheza.cz> wrote:
Hi
probably not most elegant and also not general but
rep(df$var[df$time==4],rle(df$group)$lengths)
or
rep(df$var[df$time==4], sapply(split(df$var,df$group), length))
shall give you desired vector.
Regards
Petr
> -----Original Message-----
> From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-
> project.org] On Behalf Of Benjamin Gillespie
> Sent: Sunday, November 17, 2013 3:47 PM
> To: r-help at r-project.org
> Subject: [R] Extract values from vector and repeat by group
>
> Hi all,
>
> I hope you can help.
>
> I have a data frame 'df':
>
> group=c(rep(1,8),rep(2,10),rep(3,11))
> var=rnorm(29)
> time=c(seq(1,8),seq(1,10),seq(1,11))
> df=data.frame(group,var,time)
>
> I would like to extract the value from 'var' for each 'group' at
> 'time'=4 and repeat these extracted values in a new vector ('new') n
> times where n is the number of rows for each group. I did this by hand
> as below, but there must be a quicker way:
>
> subset=subset(df,df$time==4)
> subset
> group var time
> 4 1 0.2531270 4
> 12 2 -0.3600128 4
> 22 3 0.4194730 4
>
> df$new=c(rep(0.2531270,8),rep(-0.3600128,10),rep(0.4194730,11))
>
> Any questions please ask,
>
> Many thanks in advance,
>
> Ben Gillespie, Research Postgraduate
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