[R] Find backward duplicates in a data frame
MacQueen, Don
macqueen1 at llnl.gov
Sat Nov 16 00:43:11 CET 2013
So rows are considered duplicated if they have the same two characters,
regardless of which column they're in?
If the B A row came first is it ok to keep that row, or would you want to
keep the A B row?
This appears to work, at least for this example.
foo <- t(apply(test,1, function(x) sort(format(x)) ))
test[ !duplicated(foo),]
a u
1 A B
2 A C
4 B F
6 D W
Note that the function sorts the formatted value, in case the factor
levels are such that they don't sort alphabetically.
Notice also that in the result, the second column ('u') is still a factor,
and its levels still include 'A', even though A no longer is present in
the column. Whether or not that's wanted, I couldn't say.
-Don
--
Don MacQueen
Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062
On 11/15/13 1:26 PM, "Hermann Norpois" <hnorpois at gmail.com> wrote:
>Hello,
>
>I am looking for a method to eliminate rows dupblicates in a backwards
>manner, for instance:
>I want to keep A B but not B A (see my data.frame test).
>Thanks
>Hermann
>
>> test
> a u
>1 A B
>2 A C
>3 B A
>4 B F
>5 C A
>6 D W
>> dput (test)
>structure(list(a = structure(c(1L, 1L, 2L, 2L, 3L, 4L), .Label = c("A",
>"B", "C", "D"), class = "factor"), u = structure(c(2L, 3L, 1L,
>4L, 1L, 5L), .Label = c("A", "B", "C", "F", "W"), class = "factor")),
>.Names = c("a",
>"u"), row.names = c(NA, -6L), class = "data.frame")
>
> [[alternative HTML version deleted]]
>
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