[R] Replace element with pattern
arun
smartpink111 at yahoo.com
Fri Nov 1 14:09:49 CET 2013
Hi,
Try this:
Lines1 <- readLines(textConnection("Peak Usage : init:2359296, used:15859328, committed:15892480,max:50331648Current Usage : init:2359296 used:15857920,committed:15892480,max:50331648|-------------------|
Peak Usage : init:2359296, used:15859328, committed:15892480,max:50331648Current Usage : init:2359296 used:15857920,committed:15892480,max:50331648|-------------------|"))
data.frame(Col1=as.matrix(gsub("(.*?[/|])","\\1",Lines1))) #Assuming that you want to read it from Peak Usage to the first "|":
#If it is from Current Usage to "|"
data.frame(Col1=as.matrix(gsub("^.*(Current.*?[/|]).*","\\1",Lines1)))
A.K.
On Friday, November 1, 2013 4:11 AM, "mohan.radhakrishnan at polarisft.com" <mohan.radhakrishnan at polarisft.com> wrote:
Hi,
I have a data frame with one column and several rows of the form.
"Peak Usage : init:2359296, used:15859328, committed:15892480,
max:50331648Current Usage : init:2359296, used:15857920,
committed:15892480, max:50331648|-------------------|"
I tested the regex
Current.*?[\|]
in an online tester which greedily matches upto the first 'pipe' character
Current Usage : init:2359296, used:15857920, committed:15892480,
max:50331648|
This is what I want.
I tried to replace the entire rows using
apply( y, 1, function(x) gsub(x,"Current.*?[/|]",x)) which didn't work.
How is this done ? I also want to recursively apply some more patterns one
by one on the rows till I reduce it to exactly what I want. Is there a way
to do this without loops ?
Thanks,
Mohan
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