# [R] Count number of consecutive zeros by group

PIKAL Petr petr.pikal at precheza.cz
Fri Nov 1 11:01:52 CET 2013

```Hi

Another option is sapply/split/sum construction

with(data, sapply(split(x, ID), function(x) sum(x==0)))

Regards
Petr

> -----Original Message-----
> From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-
> project.org] On Behalf Of Carlos Nasher
> Sent: Thursday, October 31, 2013 6:46 PM
> To: S Ellison
> Cc: r-help at r-project.org
> Subject: Re: [R] Count number of consecutive zeros by group
>
> If I apply your function to my test data:
>
> ID <- c(1,1,1,2,2,3,3,3,3)
> x <- c(1,0,0,0,0,1,1,0,1)
> data <- data.frame(ID=ID,x=x)
> rm(ID,x)
>
> f2 <-   function(x) {
>   max( rle(x == 0)\$lengths )
> }
> with(data, tapply(x, ID, f2))
>
> the result is
> 1 2 3
> 2 2 2
>
> which is not what I'm aiming for. It should be
> 1 2 3
> 2 2 1
>
> I think f2 does not return the max of consecutive zeros, but the max of
> any consecutve number... Any idea how to fix this?
>
>
> 2013/10/31 S Ellison <S.Ellison at lgcgroup.com>
>
> >
> >
> > > -----Original Message-----
> > > So I want to get the max number of consecutive zeros of variable x
> > > for
> > each
> > > ID. I found rle() to be helpful for this task; so I did:
> > >
> > > FUN <- function(x) {
> > >   rles <- rle(x == 0)
> > > }
> > > consec <- lapply(split(df[,2],df[,1]), FUN)
> >
> > You're probably better off with tapply and a function that returns
> > what you want. You're probably also better off with a data frame name
> > that isn't a function name, so I'll use dfr instead of df...
> >
> > dfr<- data.frame(x=rpois(500, 1.5), ID=gl(5,100)) #5 ID groups
> > numbered 1-5, equal size but that doesn't matter for tapply
> >
> > f2 <-   function(x) {
> >         max( rle(x == 0)\$lengths )
> > }
> > with(dfr, tapply(x, ID, f2))
> >
> >
> > S Ellison
> >
> >
> > *******************************************************************
> > This email and any attachments are confidential. Any
> > u...{{dropped:24}}
>
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