[R] Using loop for applying function on matrix
Pascal Oettli
kridox at ymail.com
Tue May 21 11:27:53 CEST 2013
Hello,
If you *really* need a loop:
Data <- array(NA, dim(mdat))
for(i in 1:ncol(mdat)){
Data[,i] <- mdat[,i]*100/x[i]
}
But I would consider first the thread cited by Berend.
Regards,
Pascal
On 05/21/2013 06:19 PM, Suparna Mitra wrote:
> Thanks for your reply Pascal.
> I am presently using it with sweep. But here in the question I just
> gave one simple example. In reality I need several functions to run.
> Thus I was wondering, if without sweep, I can use loop. Also want to
> learn how to do this using loop.
> Any help will be really great,
> Thanks,
> Mitra
>
> Dr. Suparna Mitra
> Department of Molecular and Clinical Pharmacology
> Institute of Translational Medicine University of Liverpool
> Block A: Waterhouse Buildings
> 1-5 Brownlow Street
> Liverpool
> L69 3GL
>
> Tel. +44 (0)151 795 5414
> M: +44 (0) 7523228621
> Internal ext: 55401
>
>
>
> On 21 May 2013 16:29, Pascal Oettli <kridox at ymail.com
> <mailto:kridox at ymail.com>> wrote:
>
> Hi,
>
> ?sweep
>
> mdat <-
> matrix(c(1,11,2,10,5,2,12,3,9,__6,3,13,4,8,7,4,10,5,9,8,5,10,__6,10,4),5,5)
> x <- c(14,15,10,11,18)
>
> sweep(mdat*100, 2, x, FUN='/')
>
> [,1] [,2] [,3] [,4] [,5]
> [1,] 7.142857 13.33333 30 36.36364 27.77778
> [2,] 78.571429 80.00000 130 90.90909 55.55556
> [3,] 14.285714 20.00000 40 45.45455 33.33333
> [4,] 71.428571 60.00000 80 81.81818 55.55556
> [5,] 35.714286 40.00000 70 72.72727 22.22222
>
> Hope this helps,
> Pascal
>
>
>
> On 05/21/2013 04:16 PM, Suparna Mitra wrote:
>
> Hello R Experts,
> I need a bit of help in using loop.
> I have a matrix onto which I need to use several functions.
>
> In a simplified form suppose my matrix is
>
> mdat
>
> [,1] [,2] [,3] [,4] [,5]
> [1,] 1 2 3 4 5
> [2,] 11 12 13 10 10
> [3,] 2 3 4 5 6
> [4,] 10 9 8 9 10
> [5,] 5 6 7 8 4
>
> And I have one vector
>
> x
>
> [1] 14 15 10 11 18
>
> Now suppose in simple form I want to create a matrix in which
> each col
> value will be divided with consecutive no from vector x. For example
>
> column 1 of new vector will be C1=mdat[,1]*100/x[1]
>
> C1
>
> [1] 7.142857 78.571429 14.285714 71.428571 35.714286
>
> Now how can I use the loop to have the complete vector at a time?
> I tried something like this, but in vain.
> for(i in 1:5) {
> Data=(mdat[,i]*100/x[i], add=T)
> }
>
> Any help will be really great.
> Thanks,
> Mitra
>
> [[alternative HTML version deleted]]
>
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