[R] load() into a data frame with my chosen name => .ThisEnv ?

[Neal Fultz]

For your problem, you might want to use saveRDS and readRDS instead of
save and load. I would also use dir to get a list of files rather
than paste. 

Then your solution might look like:


run <- function(filename) {
    df <- readRDS(filename);
    coef( lm(df[,1] ~ df[,2]) ) 
}

results <- lapply( dir(pattern=glob2rx('d*.rds')), run)

If this is disk-bound, using multiple threads probably won't help much.
You'll have to try it out for yourself.

-nfultz

On Mon, Jun 17, 2013 at 04:07:50PM -0700, ivo welch wrote:
> very simple question.  I probably forgot the answer (early stage onset),
> and I could not find it via google and r-help.
> 
> I have a number of files, each containing one saved data frame.  I want to
> do the equivalent of
> 
>    d <- .GlobalEnv[[ load(file="dxxxx.Rdata") ]
> 
> but inside a function, and I don't need the original name (dxxxx).  in the
> end, I want to do something like
> 
>    run <- function( i ) {
>         fname <- paste0( "d", i, ".Rdata")
>         stopifnot( length(fname)==1 )
>         d <- .ThisEnv[[ load(file=fname) ]]
>         coef( lm(d[,1] ~ d[,2]) )  ## calculate two coefficients and return
> them
>    }
> 
>    results <- mclapply( 1:10000, run )
> 
> stumped over something that should be easy...pointer appreciated.
> 
> /iaw
> ----
> Ivo Welch (ivo.welch at gmail.com)
> 
> 	[[alternative HTML version deleted]]
> 
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