[R] split and common variables

[David Carlson]

It may be easier if you convert the list you provided to a
data.frame:

> dta.df <- data.frame(place=dta$place, name=dta$name,
value=dta$value)
> dta.df

Note that the last line is blank so you probably want to remove that
and remove the blank factor levels:

> dta.df <- dta.df[-nrow(dta.df),]
> dta.df$place <- factor(dta.df$place)
> dta.df$name <- factor(dta.df$name)
> dta.df

Now you can make a list containing separate data.frames by place 

> dta.df.sp <- split(dta.df, dta.df$place)
> dta.df.sp

-------------------------------------
David L Carlson
Associate Professor of Anthropology
Texas A&M University
College Station, TX 77840-4352


-----Original Message-----
From: r-help-bounces at r-project.org
[mailto:r-help-bounces at r-project.org] On Behalf Of Nico Met
Sent: Monday, June 3, 2013 8:42 AM
To: R help
Subject: [R] split and common variables

Dear all,

I would like to split the data based on the "place" and then would
like to
see how many "names" were common in place with corresponding "value"
.

Please find a demo file.

Thanks for your expert comment

best

Nico

> dput(dta)
structure(list(place = structure(c(3L, 2L, 5L, 6L, 4L, 3L, 2L,
5L, 6L, 4L, 2L, 5L, 6L, 4L, 2L, 5L, 6L, 4L, 2L, 3L, 2L, 5L, 6L,
4L, 3L, 2L, 5L, 6L, 4L, 5L, 6L, 4L, 5L, 6L, 1L), .Label = c("",
"GCKT", "IKLI", "KLOI", "PLRT", "POIV"), class = "factor"), name =
structure
(c(2L,
3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L, 11L, 12L, 2L, 3L, 4L, 5L, 6L,
7L, 8L, 9L, 10L, 11L, 12L, 2L, 3L, 4L, 5L, 6L, 7L, 8L, 9L, 10L,
11L, 12L, 12L, 1L), .Label = c("", "P_CK23", "P_CK24", "P_CK25",
"P_CK26", "P_CK27", "P_CK28", "P_CK29", "P_CK30", "P_CK31",
"P_CK32",
"P_CK33"), class = "factor"), value = c(5.9464, 6.0786, -4.5155,
15.0241, -38.1847, -0.0861, 1.2757, -23.9914, 9.5951, -11.128,
6.2826, 23.5218, 20.862, 3.1626, 6.242, -20.5348, -14.0126, -13.796,
15.3869, -15.7409, -8.1963, -14.4522, 3.2117, -1.2738, 14.3556,
-12.5337, 20.4308, -3.3227, -34.802, -11.1103, -9.7146, -35.9044,
-9.4303, -28.1949, NA)), .Names = c("place", "name", "value"), class
= "data
.frame", row.names = c(NA,
35L))
>

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