[R] simplify a dataframe

[Arnaud Michel]

  Thank you for the question (1)
Sorry for the imprecision for the question (2) :
Suppose the date frame df
df1 <- data.frame(
Debut =c ( "24/01/1995", "01/05/1997" ,"31/12/1997", "02/02/1995" 
,"28/02/1995"
,"01/03/1995", "13/03/1995", "01/01/1996", "31/01/1996") ,
Fin = c ( "30/04/1997", "30/12/1997" ,"31/12/1997", "27/02/1995", 
"28/02/1995",
"12/03/1995", "30/06/1995", "30/01/1996", "31/01/1996") ,
INDX = c(6,6,6,  11,11,11, 4,  5,5) )


I would like replace df1  by df2

df2 <- data.frame(
Deb  = c("24/01/1995",     "02/02/1995",     "13/03/1995",
"01/01/1996") ,
Fin  = c("31/12/1997", "12/03/1995",     "30/06/1995",
"31/01/1996") )

Explication :
The lines 1, 2 3 of df1 (who have same value of index =6) are replaced 
by only one line with
value of Debut of df2 = Debut of line 1 of df1
value of Fin of df2 = Fin of line 3 of df1

The lines 4,5,6 of df1 (who have same value of index =11) are replaced 
by only one line with
value of Debut of df2 = Debut of line 4 of df1
and value of fin of df2 = Fin of line 6 of df1

The line 7 of df1 (who have same value of index =4) are replaced by only 
one line with
value of Debut of df2 = Debut of line 7of df1
and value of fin of df2 = Fin of line 7of df1
==> No change

The lines 8,9 of df1 (who have same value of index =5) are replaced by 
only one line with
value of Debut of df2 = Debut of line 8of df1
and value of fin of df2 = Fin of line 9 of df1

df1
        Debut        Fin INDX
1 24/01/1995 30/04/1997    6
2 01/05/1997 30/12/1997    6
3 31/12/1997 31/12/1997    6
4 02/02/1995 27/02/1995   11
5 28/02/1995 28/02/1995   11
6 01/03/1995 12/03/1995   11
7 13/03/1995 30/06/1995    4
8 01/01/1996 30/01/1996    5
9 31/01/1996 31/01/1996    5

          Deb        Fin
1 24/01/1995 31/12/1997
2 02/02/1995 12/03/1995
3 13/03/1995 30/06/1995
4 01/01/1996 31/01/1996
Thank you for your helps
Michel

Le 17/07/2013 19:57, Rui Barradas a écrit :
> Hello,
>
> As for question (1), try the following.
>
>
> y2 <- cumsum(c(TRUE, diff(x1) > 0))
> identical(as.integer(y1), y2)  # y1 is of class "numeric"
>
>
> As for question (2) I'm not understanding it.
>
> Hope this helps,
>
> Rui Barradas
>
> Em 17-07-2013 18:21, Arnaud Michel escreveu:
>> Hi Arun
>>
>> I have two questions always about the question of symplify a dataframe
>>
>> I would like
>> 1)  to transform the vector x1 into the vector y1
>> x1 <- c(1,1,1,-1000,         1,-1000, 1,1,1,1,1,1,-1000)
>> y1 <- c(1,1,1,1,                    2,2, 3,3,3,3,3,3,3)
>>
>>
>> 2) to transform the vectors Debut and Fin by taking into account INDX
>> into the two vectors Deb and Fin
>> Debut <- c (
>> "24/01/1995", "01/05/1997" ,"31/12/1997", "02/02/1995" ,"28/02/1995"
>> ,"01/03/1995",
>> "13/03/1995", "01/01/1996", "31/01/1996", "24/01/1995", "01/07/1995"
>> ,"01/09/1995",
>>    "01/07/1997", "01/01/1998", "01/08/1998", "01/01/2000",
>> "17/01/2000","29/02/2000")
>>
>> Fin <- c (
>> "30/04/1997", "30/12/1997" ,"31/12/1997", "27/02/1995", "28/02/1995",
>> "12/03/1995",
>> "30/06/1995", "30/01/1996", "31/01/1996", "30/06/1995", "31/08/1995",
>> "30/06/1997",
>> "31/12/1997", "31/07/1998", "31/12/1999", "16/01/2000", "28/02/2000",
>> "29/02/2000")
>>
>> INDX <- c(6,6,6,                    11,11,11, 4,        5,5)
>>
>>
>> Deb  <- c("*24/01/1995*",     "*02/02/1995*", "*13/03/1995*",
>> "*01/01/1996*")
>> Fi n  <-  c("*31/12/1997*", "*12/03/1995*", "*30/06/1995*",
>> "*31/01/1996*")
>>
>>
>>        Debut        Fin INDX
>> *24/01/1995* 30/04/1997    6
>> 01/05/1997 30/12/1997    6
>> 31/12/1997 *31/12/1997*    6
>> *02/02/1995* 27/02/1995   11
>> 28/02/1995 28/02/1995   11
>> 01/03/1995 *12/03/1995*   11
>> *13/03/1995* *30/06/1995*    4
>> *01/01/1996* 30/01/1996    5
>> 31/01/1996 *31/01/1996*    5
>> ................
>>
>> Thanks for your help
>>
>>
>>
>> ______________________________________________
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>> PLEASE do read the posting guide 
>> http://www.R-project.org/posting-guide.html
>> and provide commented, minimal, self-contained, reproducible code.
>>
>

-- 
Michel ARNAUD
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