[R] How to extract values of results in gamlss.tr
dwinsemius at comcast.net
Wed Jan 23 21:42:39 CET 2013
On Jan 23, 2013, at 12:14 PM, Katherine Gobin wrote:
> Dear R helpers,
> I have following loss data and I need to fit LEFT truncated Log Normal distribution to this data which is Truncated at 1000000.
> dat = c(1333834,5710254,9987567,7809469,6940935,3473671,1270209,1102523,1124002, 5830159,4302300,3925242,2638409,2324421,7238436,9088709,7439250,4976551,4864319, 8741334,1863770,7098310,4942288,4971829,4986372)
> gen.trun(5, LOGNO)
> result <- gamlss(dat~1, family=LOGNOtr)
> # THIS GIVES
> Family: c("LOGNOtr", "left truncated Log Normal")
> Fitting method: RS()
> Call: gamlss(formula = dat ~ 1, family = LOGNOtr)
> Mu Coefficients:
> Sigma Coefficients:
> Degrees of Freedom for the fit: 2 Residual Deg. of Freedom 23
> Global Deviance: 812.568
> AIC: 816.568
> SBC: 819.006
> My problem is how do I extract these values of Mu Coefficients and Sigma Coefficients, if I want to use these values for further analyses?
After looking at names(result)
I looked for an extractor function in hte Index for htat package but didn't find one. Since this is a suite of packages you should probably do your own more extensive search in the documents.
Alameda, CA, USA
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