[R] Integration in R
David Winsemius
dwinsemius at comcast.net
Tue Jan 8 22:31:02 CET 2013
On Jan 8, 2013, at 1:07 PM, Berend Hasselman wrote:
>
> On 08-01-2013, at 22:00, Berend Hasselman <bhh at xs4all.nl> wrote:
>
>> …...
>> David implemented the condition by multiplying by x[1]<x[2] which
>> in a numeric context is 0 when x[1]<x[2] en 1 when x[1]>=x[2].
>
> OOPS!! Reverse the 0 and the 1 in that sentence (TRUE becomes 1 and
> FALSE becomes 0)
I didn't worry about which direction was used for the inequality in
this case because of consideration of symmetry. (Thinking about it
now, I still think I managed to choose the correct direction.)
Obviously such a cavalier attitude should not be carried over to the
general situation.
--
David Winsemius, MD
Alameda, CA, USA
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