[R] how to

[PIKAL Petr]

Hi

So why you do not assign it inside a cycle? As I said lapply does the same as for cycle does (maybe in some more compact manner).

Regards
Petr

> -----Original Message-----
> From: Simone Gabbriellini [mailto:simone.gabbriellini at gmail.com]
> Sent: Friday, February 01, 2013 2:29 PM
> To: PIKAL Petr
> Cc: r-help at r-project.org
> Subject: Re: [R] how to
> 
> Hi,
> 
> Yes I know it works, but I'd like to assign the results like this:
> 
> V(g)$meanknn <- ONELINER
> 
> Where V(g) elencates all the nodes in my graph...
> 
> Thanks,
> Simone
> 
> Sent from my iPhone. Please excuse brevity and odd typos
> 
> On 01/feb/2013, at 13:31, PIKAL Petr <petr.pikal at precheza.cz> wrote:
> 
> > Hi
> >
> > I do not see any problem with your code. *apply functions are also
> hidden cycles and there shall not be substantial improvement in speed.
> >
> > Why you do not want to use for cycle?
> >
> > Petr
> >
> >
> >> -----Original Message-----
> >> From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-
> >> project.org] On Behalf Of Simone Gabbriellini
> >> Sent: Friday, February 01, 2013 12:54 PM
> >> To: r-help at r-project.org
> >> Subject: [R] how to
> >>
> >> Dear List,
> >>
> >> I have a list of lists and on each list I want to apply a function
> >> from the igraph package, graph.knn. I need to calculate graph.knn
> for
> >> each list on a graph g, then retrieve one of the result called $knn
> >> and calculate its mean. The non-R style code looks like this:
> >>
> >> for(i in listOfLists){
> >>    print(mean(graph.knn(g, i)$knn))
> >> }
> >>
> >> Is there any way to convert this in a one-liner? I have tried to
> >> figure it out with lapply() or mapply() but with no success.
> >>
> >> Thank you in advance for your help.
> >>
> >> Simone
> >>
> >> --
> >> Simone Gabbriellini, PhD
> >>
> >> PostDoc at DISI, University of Bologna
> >> mobile: +39 340 39 75 626
> >> email: simone.gabbriellini at unibo.it
> >> home: www.digitaldust.it
> >>
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> >>
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