[R] The time unit of strptime() after performing arithmetic calculation

[MacQueen, Don]

The Details section of the help page for difftime explains why.

-- 
Don MacQueen

Lawrence Livermore National Laboratory
7000 East Ave., L-627
Livermore, CA 94550
925-423-1062





On 8/9/13 11:02 AM, "Jun Shen" <jun.shen.ut at gmail.com> wrote:

>Thanks Jim and David,
>
>The difftime() is exactly what I am looking for. Just out of curiosity why
>the unit of output is different. here is an example of the dataframe.
>
>test<-structure(list(SPDTC = c("2012-08-27T09:30", "2012-08-06T10:08",
>"2012-08-13T07:41", "2012-07-17T07:50", "2012-09-11T10:29"),
>    TimeBL = c("2012-07-17T07:50", "2012-07-17T07:50", "2012-07-17T07:50",
>    "2012-07-17T07:50", "2012-07-17T07:50")), .Names = c("SPDTC",
>"TimeBL"), row.names = c(NA, 5L), class = "data.frame")
>
>Here is the calculation I did originally.
>
>>with(test,strptime(SPDTC,format='%Y-%m-%dT%H:%M')-strptime(TimeBL,format=
>>'%Y-%m-%dT%H:%M'))
>
>The result is in seconds.
>
>
>On Fri, Aug 9, 2013 at 1:55 PM, David Winsemius
><dwinsemius at comcast.net>wrote:
>
>>
>> On Aug 9, 2013, at 10:37 AM, Jun Shen wrote:
>>
>> > Hi all,
>> >
>> > I used strptime() to convert character strings to time and did some
>> > subtraction calculation.
>> >
>> > a<-'2012-07-17T07:50'
>> > b<-'2012-08-27T09:30'
>> >
>> > 
>>strptime(a,format='%Y-%m-%dT%H:%M')-strptime(b,format='%Y-%m-%dT%H:%M')
>> >
>> > The result shows
>> >
>> > Time difference of -41.06944 days.
>> >
>> > However when these operations performed in a dataframe, the time
>> difference
>> > is in the unit of seconds. Why is that? What I really want is in
>>hours. I
>> > know I can convert the results manually to hours but just wonder if
>>there
>> > is way to control the unit. Thanks.
>>
>> ?difftime
>> ?`-.POSIXt`
>>
>> Should provide exactly what is requested (and is linked from the
>> ?DateTimeClasses help page.)
>>
>> --
>> David Winsemius
>> Alameda, CA, USA
>>
>>
>
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>
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