[R] list of funtions

[Jonathan Phillips]

Yes, seen it, and it's obviously the wrong thing to do or I'd be
getting the result I'm looking for.  But I can't see the correct way
of doing it.  I.e. I can't see any way of setting each element of the
list to a function with a different 'form' value without using some
'i' like variable in a loop.
I don't think it's something obvious I've missed...

On 13 September 2012 18:06, Uwe Ligges <ligges at statistik.tu-dortmund.de> wrote:
>
>
> On 13.09.2012 19:01, Jonathan Phillips wrote:
>>
>> Hi,
>> I have a function called fitMicroProtein which takes a value called
>> form, this can be any integer from 0-38.
>> In a larger function I'm making (it's called Newton), the first thing
>> I want to do is construct a list of functions where form is already
>> set.  So in pseudocode
>>
>> fs[[1]](...) <- fitMicroProtein(form=0,...)
>> fs[[2]](...) <- fitMicroProtein(form=1,...)
>> .
>> .
>> .
>>
>> I've tried that and it doesn't work.  Here's my code:
>>
>> Newton <- function(metaf,par,niter,dealwith_NA,...)
>> {
>>          fs <- list()
>>          for(i in 0:(length(par)-1))
>>          {
>>                  fs[[i+1]] <- function(par) return(metaf(par,form=i,...))
>>                  }
>> .
>> .
>> .
>>
>>
>> and the problem is with the variable 'i'.
>> If I use the debugger, I find that it is specifically that:
>>
>> When it makes f[[1]] we have
>>     f[[1]] == function(par) return(metaf(par,form=0,...)
>> but the next thing it does is increment 'i', so f[[1]] becomes
>>     function(par) return(metaf(par,form=1,...)
>> where I want f[[1]] to stay as
>>     function(par) return(metaf(par,form=0,...)
>>
>> Does anybody know how to stop the value of f[[1]] being dependant on
>> the current value of 'i'?
>
>
> Er, you know that you have
>
>  function(par) return(metaf(par,form=i,...))
>
> in your loop. If you want to have it independent if i, why do you specify
> it?
>
> Uwe Ligges
>
>>
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>>
>