[R] splits with 0s in middle columns

[arun]

Hi,
It's working for me.
Try this:
dat1<-read.csv("test.csv")
dat2<-na.omit(dat1)
 
nrow(dat1)
#[1] 635
 nrow(dat2)
#[1] 627

B<-gsub(" slope{0,1}\\s\\((.*)\\)","\\1",dat2$Composition_percent_part)
fun1<-function(x){
C<-gsub("(.*)/(.*)","\\1 0 0 \\2", gsub("(.*)/(.*)/(.*)","\\1 \\2 0 \\3", gsub("(.*)/(.*)/(.*)/(.*)","\\1 \\2 \\3 \\4",x)))
res<-data.frame(do.call(rbind,strsplit(C," ")))
colnames(res)<-paste("A",1:4,sep="")
res
}
fun1(B)
head(fun1(B),15)
 #  A1 A2 A3 A4
#1  60 25  0 15
#2  60 25  0 15
#3  40 35 15 10
#4  40 35 15 10
#5  40 35 15 10
#6  40 35 15 10
#7  40 35 15 10
#8  50 40  0 10
#9  50 40  0 10
#10 50 40  0 10
#11 50 40  0 10
#12 50 30  0 20
#13 50 30  0 20
#14 50 30  0 20
#15 50 30  0 20

#or,
fun1<-function(x){
B<-gsub(" slope{0,1}\\s\\((.*)\\)","\\1",x)
C<-gsub("(.*)/(.*)","\\1 0 0 \\2", gsub("(.*)/(.*)/(.*)","\\1 \\2 0 \\3", gsub("(.*)/(.*)/(.*)/(.*)","\\1 \\2 \\3 \\4",B)))
res<-data.frame(do.call(rbind,strsplit(C," ")))
colnames(res)<-paste("A",1:4,sep="")
res
}
fun1(dat2$Composition_percent_part)    


 head(fun1(dat2$Composition_percent_part),5)
#  A1 A2 A3 A4
#1 60 25  0 15
#2 60 25  0 15
#3 40 35 15 10
#4 40 35 15 10
#5 40 35 15 10



A.K.




________________________________
From: Sapana Lohani <lohani.sapana at ymail.com>
To: arun <smartpink111 at yahoo.com> 
Sent: Sunday, September 2, 2012 8:39 PM
Subject: Re: [R] splits with 0s in middle columns


Hi Arun,

I do not know whats wrong with 
my data, so am sending you the whole column I wanted to split. Could you please have a look and suggest me the error? I ma totally stuck at this point of my analysis



________________________________
From: arun <smartpink111 at yahoo.com>
To: Rui Barradas <ruipbarradas at sapo.pt> 
Cc: Sapana Lohani <lohani.sapana at ymail.com>; R help <r-help at r-project.org> 
Sent: Sunday, September 2, 2012 1:54 PM
Subject: Re: [R] splits with 0s in middle columns

HI,
You can also try this as a function:
fun1<-function(x){
B<-gsub("percent{0,1}\\s\\((.*)\\)","\\1",x)
C<-gsub("(.*)/(.*)","\\1 0 0 \\2", gsub("(.*)/(.*)/(.*)","\\1 \\2 0 \\3", gsub("(.*)/(.*)/(.*)/(.*)","\\1 \\2 \\3 \\4",B)))
dat1<-data.frame(do.call(rbind,strsplit(C," ")))
colnames(dat1)<-paste0("A",1:4)
dat1
}
 fun1(A)
#  A1 A2 A3 A4
#1 10 20  0 30
#2 40  0  0 20
#3 60 10 10  5
#4 80  0  0 10
A.K.




----- Original Message -----
From: Rui Barradas <ruipbarradas at sapo.pt>
To: Sapana Lohani <lohani.sapana at ymail.com>
Cc: r-help <r-help at r-project.org>
Sent: Sunday,
September 2, 2012 1:05 PM
Subject: Re: [R] splits with 0s in middle columns

Hello,

You don't need a new function, what you need is to prepare your data in 
such a way that the function can process it.


A <- c("percent (10/20/30)", "percent (40/20)", "percent (60/10/10/5)",
"percent (80/10)")
B <- gsub("\\(|\\)|percent| ", "", A)
fun(B)

Also, please use dput to post the data examples,

dput(A)
c("percent (10/20/30)", "percent (40/20)", "percent (60/10/10/5)",
"percent (80/10)")

Then copy&paste in your post.

Rui Barradas

Em 02-09-2012 04:22, Sapana Lohani escreveu:
> Dear Rui,
>
> The new code works fine for what I wanted. I have another similar column but it looks like
>
> A
> percent (10/20/30)
> percent (40/20)
> percent (60/10/10/5)
> percent (80/10)
>
> I want a similar split but delete the percent
in the front. The output should look like
>
> A1 A2 A3 A4
> 10 20 0 30
> 40 0 0 20
> 60 10 10 5
> 80 0 0 10
>
> Could you please make the small change in the code that you gave me. It must be a small edition but I could not figure that out. FYI the code that worked was
>
> fun <- function(X){
>       xname <- deparse(substitute(X))
>       s <- strsplit(X, "/")
>       n <- max(sapply(s, length))
>       tmp <- numeric(n)
>
>       f <- function(x){
>           x <- as.numeric(x)
>           m <- length(x)
>           if(m > 1){
>               tmp[n] <- x[m]
>   
           tmp[seq_len(m - 1)] <- x[seq_len(m - 1)]
>           }else tmp[1] <- x
>           tmp
>       }
>
>       res <- do.call(rbind, lapply(s, f))
>       colnames(res) <- paste(xname, seq_along(s), sep = "")
>       data.frame(res)
> }
>
> fun(A)
>
> Thank you so very much.

______________________________________________
R-help at r-project.org mailing list
https://stat.ethz.ch/mailman/listinfo/r-help
PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
and provide commented, minimal, self-contained,
reproducible code.