[R] R_closest date

[arun]

Hi,
Try this:
dat1 <- read.table(text="
  PT_ID    IDX_DT  OBS_DATE DAYS_DIFF OBS_VALUE CATEGORY
13  4549 2002-08-21 2002-08-20        -1      183        2
14  4549 2002-08-21 2002-11-14        85        91        1
15  4549 2002-08-21 2003-02-18      181        89        1
16  4549 2002-08-21 2003-05-15      267      109        2
17  4549 2002-08-21 2003-12-16      482        96        1
128  4839 2006-11-28 2006-11-28        0      179        2
", header=TRUE)
dat3<-aggregate(DAYS_DIFF~PT_ID,data=dat1,min)
merge(dat1,dat3)
#  PT_ID DAYS_DIFF     IDX_DT   OBS_DATE OBS_VALUE CATEGORY
#1  4549        -1 2002-08-21 2002-08-20       183        2
#2  4839         0 2006-11-28 2006-11-28       179        2

#or,
dat2<- tapply(dat1$DAYS_DIFF,dat1$PT_ID,min)
dat4<-data.frame(PT_ID=row.names(data.frame(dat2)),DAYS_DIFF=dat2)
 row.names(dat4)<-1:nrow(dat4)
merge(dat1,dat4)
#  PT_ID DAYS_DIFF     IDX_DT   OBS_DATE OBS_VALUE CATEGORY
#1  4549        -1 2002-08-21 2002-08-20       183        2
#2  4839         0 2006-11-28 2006-11-28       179        2
A.K.





----- Original Message -----
From: WANG WEIJIA <wwang.nyu at gmail.com>
To: "r-help at R-project.org" <r-help at r-project.org>
Cc: 
Sent: Saturday, September 1, 2012 1:10 PM
Subject: [R] R_closest date

Hi, 

I have encountered an issue about finding a date closest to another date

So this is how the data frame looks like:

    PT_ID     IDX_DT   OBS_DATE DAYS_DIFF OBS_VALUE CATEGORY
13   4549 2002-08-21 2002-08-20        -1       183        2
14   4549 2002-08-21 2002-11-14        85        91        1
15   4549 2002-08-21 2003-02-18       181        89        1
16   4549 2002-08-21 2003-05-15       267       109        2
17   4549 2002-08-21 2003-12-16       482        96        1
128  4839 2006-11-28 2006-11-28         0       179        2

I need to find, the single observation, which has the closest date of 'OBS_DATE' to 'IDX_DT'.

For example, for 'PT_ID' of 4549, I need row 13, of which the OBS_DATE is just one day away from IDX_DT. 

I was thinking about using abs(), and I got this:

baseline<- function(x){
+  
+  #remove all uncessary variables
+  baseline<- x[,c("PT_ID","DAYS_DIFF")]
+  
+  #get a list of every unique ID
+  uniqueID <- unique(baseline$PT_ID)
+  
+  #make a vector that will contain the smallest DAYS_DIFF
+  first <- rep(-99,length(uniqueID))
+  
+  i = 1
+  #loop through each unique ID
+  for (PT_ID in uniqueID){
+  
+  #for each iteration get the smallest DAYS_DIFF for that ID
+  first[i] <- min(baseline[which(baseline$PT_ID==PT_ID),abs(baseline$DAYS_DIFF)])
+  
+  #up the iteration counter
+  i = i + 1
+  
+  }
+  #make a data frame with the lowest DAYS_DIFF and ID
+  newdata <- data.frame(uniqueID,first)
+  names(newdata) <- c("PT_ID","DAYS_DIFF")
+  
+  #return the data frame containing the lowest GPI for each ID
+  return(newdata)
+  }
> ldl.b<-baseline(ldl) #get all baseline ldl patient ID, total 11368 obs, all unique#
Error in `[.data.frame`(baseline, which(baseline$PT_ID == PT_ID), abs(baseline$DAYS_DIFF)) : 
  undefined columns selected

Can anyone help me in figuring out how to get the minimum value of the absolute value of DAYS_DIFF for unique ID?

Thanks a lot
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