[R] help - extract data using column names

jim holtman jholtman at gmail.com
Tue Oct 30 17:05:10 CET 2012


Is this what you want:

> x <- read.table(text = "            Mi         RBN         RBF        nDB         nX
+ 3   2.6225979  0.53132756 -0.80599902 -1.4471864 -0.5705269
+ 10  0.4818746 -1.72143092 -2.19579027  2.0118824 -0.5705269
+ 12  2.8519611  1.88298265  0.09614617  0.6282549 -0.5705269
+ 20  0.6347834 -0.36977583  0.63255683  1.3200687 -0.5705269", header = TRUE)
>
> extract <- c("Mi", "nX")
> x[, extract]
          Mi         nX
3  2.6225979 -0.5705269
10 0.4818746 -0.5705269
12 2.8519611 -0.5705269
20 0.6347834 -0.5705269


On Tue, Oct 30, 2012 at 10:09 AM, alex_123 <deepak.juit at gmail.com> wrote:
> hello , I am new user in R . I have datafile (class = data.frame) which has
> 825 columns with unique column name i want extract 200 selected column from
> datafile how can I do this?
> my datafile look like..
>             Mi         RBN         RBF        nDB         nX
> 3   2.6225979  0.53132756 -0.80599902 -1.4471864 -0.5705269
> 10  0.4818746 -1.72143092 -2.19579027  2.0118824 -0.5705269
> 12  2.8519611  1.88298265  0.09614617  0.6282549 -0.5705269
> 20  0.6347834 -0.36977583  0.63255683  1.3200687 -0.5705269
>
>
> I want to extract data with unique name of column  , by  "Mi","RBF" etc . I
> have stored character vector of desired column names. eg  aa =
> c("Mi","RBF",..)
>
>
>
>
>
> --
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> Sent from the R help mailing list archive at Nabble.com.
>
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-- 
Jim Holtman
Data Munger Guru

What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.




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