[R] newbie: embeding seq in a list

[Jessica Streicher]

s <- seq(0.8, 1.2, by = 0.1)
as.list(s)

to get the first type of list from the sequence.

On 30.10.2012, at 16:51, ONKELINX, Thierry wrote:

> You first example is a list of 5 items, each item is a number
> The second example is a list with one item: a vector with 5 elements.
> 
> You'll need c() to make a vector of the item to get the same result.
> all.equal(list(c(0.8,0.9,1.0,1.1,1.2)), list(seq(0.8, 1.2, by = 1.1)))
> 
> ir. Thierry Onkelinx
> Instituut voor natuur- en bosonderzoek / Research Institute for Nature and Forest
> team Biometrie & Kwaliteitszorg / team Biometrics & Quality Assurance
> Kliniekstraat 25
> 1070 Anderlecht
> Belgium
> + 32 2 525 02 51
> + 32 54 43 61 85
> Thierry.Onkelinx at inbo.be
> www.inbo.be
> 
> To call in the statistician after the experiment is done may be no more than asking him to perform a post-mortem examination: he may be able to say what the experiment died of.
> ~ Sir Ronald Aylmer Fisher
> 
> The plural of anecdote is not data.
> ~ Roger Brinner
> 
> The combination of some data and an aching desire for an answer does not ensure that a reasonable answer can be extracted from a given body of data.
> ~ John Tukey
> 
> 
> -----Oorspronkelijk bericht-----
> Van: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org] Namens Anser Chen
> Verzonden: dinsdag 30 oktober 2012 13:42
> Aan: r-help at r-project.org
> Onderwerp: [R] newbie: embeding seq in a list
> 
> Suppose I want to create a structure containing the following values:
> 0.8,0.9,1.0,1.1,1.2
> 
> If I use
> 
> env <- list(0.8,0.9,1.0,1.1,1.2)
> 
> then R returns
> 
>> env
> [[1]]
> [1] 0.8
> 
> [[2]]
> [1] 0.9
> 
> [[3]]
> [1] 1
> 
> [[4]]
> [1] 1.1
> 
> [[5]]
> [1] 1.2
> 
> 
> But, if I try to 'save some key-strokes', and use
> 
> 
> env <- list(seq(0.8,1.2,by=0.1))
> 
> then R returns
> 
>> env
> [[1]]
> [1] 0.8 0.9 1.0 1.1 1.2
> 
> 
> I'd like the 'latter' to be equivalent to 'the former', but can't figure out how to achieve said aim.
> 
> Thanks in advance...
> 
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> 
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