[R] Help plz to fix it

[Sarah Goslee]

This looks like homework to me.

Here's a hint, though:
p<-(1/10 2/5 2/5 2/5 2/5 1/10 1/10 1/10 1/10 1/10)
This is not how you create a vector in R.

 for (i in 1 to x)
This is not how you create a for loop in R.

Sarah


On Mon, Oct 22, 2012 at 2:41 PM, Rlotus <yerlan_ at hotmail.com> wrote:
> I have an array of probabilities....it is p. So if user types x=1 then
> probability is p1=1/10.
> If user types x=2 it means that p2= p1+p2
> if user types x=3 it means that p3=p1+p2+p3....and so on.
> So i created a code..... but it doesnt work properly. Help me plz to fix it)
> Thank u in advance.
>
> psidp=function(x){
>   p<-(1/10 2/5 2/5 2/5 2/5 1/10 1/10 1/10 1/10 1/10)
>    i==0;
>    if (x!=0){
>         for (i in 1 to x)
>         {p[i]=p[i]+p[i-1]
>         p[i]
>                 }
>
> }
>
>
>


-- 
Sarah Goslee
http://www.functionaldiversity.org