[R] cut2 error

arun smartpink111 at yahoo.com
Thu Oct 18 00:41:27 CEST 2012


Hi Charles,
Sorry, now I remember that I was working with another cut2() function (from Rui's solution) when I tried your data.

dat1<-structure(list(var1 = c(97, 97, 98, 98, 97, 99, 97,
98, 99, 98, 99, 98, 98, 97, 97, 98, 99, 98, 96, 98, 98, 99, 98,
98, 99, 99, 98, 99, 98, 99, 99, 99, 99, 98, 99, 96, 99, 98, 98,
99, 97, 98, 99, 99, 97, 99, 99, 98, 98, 98, 99, NA, 99, 98, 98,
98, 98, 98, 98, 98, 99, 99, 98, 99, 99, 98, 98, 99, 99, 97, 98,
98, 98, 99, 98, 98, 98, 99, 98, 98)), .Names = "var1", row.names = c(NA,
80L), class = "data.frame")
unique(dat1[,1])
#[1] 97 98 99 96 NA
cut2 <- function(x, g = 0){
    cut(x, breaks = c(-Inf, seq(min(x), max(x), length.out = g)))
}

dat2<-dat1[!is.na(dat1)]
cut2(dat2,g=4)

A.K.
________________________________
From: Charles Determan Jr <deter088 at umn.edu>
To: David Winsemius <dwinsemius at comcast.net> 
Cc: arun <smartpink111 at yahoo.com>; R help <r-help at r-project.org> 
Sent: Wednesday, October 17, 2012 5:04 PM
Subject: Re: [R] cut2 error


David,

I am pursuing this because this is just one variable analyzed within a loop where most have the 4 defined quartiles to assign 4 groups.  When I see that error, I wanted to understand it to see if there is something wrong.  That is why I isolated it and tried the particular variable and still got the error.  Is this something to just ignore and add a component in the loop saying there isn't four groups with that variable?

Regards


On Wed, Oct 17, 2012 at 3:58 PM, David Winsemius <dwinsemius at comcast.net> wrote:


>On Oct 17, 2012, at 1:52 PM, Charles Determan Jr wrote:
>
>
>Hi A.K.
>>
>>I tried your code exactly as you presented but I only get the following
>>output, did I somehow miss something?  Was there something else loaded?
>>Thanks,
>>
>>[1] [96, 99) [96, 99) [96, 99) [96, 99) [96, 99) 99       [96, 99) [96, 99)
>>[9] 99       [96, 99) 99       [96, 99) [96, 99) [96, 99) [96, 99) [96, 99)
>>[17] 99       [96, 99) [96, 99) [96, 99) [96, 99) 99       [96, 99) [96, 99)
>>[25] 99       99       [96, 99) 99       [96, 99) 99       99       99
>>[33] 99       [96, 99) 99       [96, 99) 99       [96, 99) [96, 99) 99
>>[41] [96, 99) [96, 99) 99       99       [96, 99) 99       99       [96, 99)
>>[49] [96, 99) [96, 99) 99       99       [96, 99) [96, 99) [96, 99) [96, 99)
>>[57] [96, 99) [96, 99) [96, 99) 99       99       [96, 99) 99       99
>>[65] [96, 99) [96, 99) 99       99       [96, 99) [96, 99) [96, 99) [96, 99)
>>[73] 99       [96, 99) [96, 99) [96, 99) 99       [96, 99) [96, 99)
>>Levels: [96, 99) 99
>>Warning message:
>>In min(xx[xx > upper]) : no non-missing arguments to min; returning Inf
>>
>>
For the quantiles requested with your data you get:
>
>> quantile(dat[1], prob=(1:4)/4, na.rm=TRUE)
> 25%  50%  75% 100%
>  98   98   99   99
>
>So you only have 2 groups in your answer. Why are you persisting in trying to do this operation when you only had 4 values to start with?
>
>-- 
>David.
>
>
>
>>On Wed, Oct 17, 2012 at 3:30 PM, arun <smartpink111 at yahoo.com> wrote:
>>
>>
>>Hi,
>>>Try this:
>>>dat1<-structure(list(var1 = c(97, 97, 98, 98, 97, 99, 97,
>>>98, 99, 98, 99, 98, 98, 97, 97, 98, 99, 98, 96, 98, 98, 99, 98,
>>>98, 99, 99, 98, 99, 98, 99, 99, 99, 99, 98, 99, 96, 99, 98, 98,
>>>99, 97, 98, 99, 99, 97, 99, 99, 98, 98, 98, 99, NA, 99, 98, 98,
>>>98, 98, 98, 98, 98, 99, 99, 98, 99, 99, 98, 98, 99, 99, 97, 98,
>>>98, 98, 99, 98, 98, 98, 99, 98, 98)), .Names = "var1", row.names = c(NA,
>>>80L), class = "data.frame")
>>>unique(dat1[,1])
>>>#[1] 97 98 99 96 NA
>>>dat2<-dat1[!is.na(dat1)]
>>>cut2(dat2,g=4)
>>># [1] (96,97]   (96,97]   (97,98]   (97,98]   (96,97]   (98,99]   (96,97]
>>>#[8] (97,98]   (98,99]   (97,98]   (98,99]   (97,98]   (97,98]   (96,97]
>>>#[15] (96,97]   (97,98]   (98,99]   (97,98]   (-Inf,96] (97,98]   (97,98]
>>>#[22] (98,99]   (97,98]   (97,98]   (98,99]   (98,99]   (97,98]   (98,99]
>>>#[29] (97,98]   (98,99]   (98,99]   (98,99]   (98,99]   (97,98]   (98,99]
>>>#[36] (-Inf,96] (98,99]   (97,98]   (97,98]   (98,99]   (96,97]   (97,98]
>>>#[43] (98,99]   (98,99]   (96,97]   (98,99]   (98,99]   (97,98]   (97,98]
>>>#[50] (97,98]   (98,99]   (98,99]   (97,98]   (97,98]   (97,98]   (97,98]
>>>#[57] (97,98]   (97,98]   (97,98]   (98,99]   (98,99]   (97,98]   (98,99]
>>>#[64] (98,99]   (97,98]   (97,98]   (98,99]   (98,99]   (96,97]   (97,98]
>>>#[71] (97,98]   (97,98]   (98,99]   (97,98]   (97,98]   (97,98]   (98,99]
>>>#[78] (97,98]   (97,98]
>>>#Levels: (-Inf,96] (96,97] (97,98] (98,99]
>>>A.K.
>>>
>>>
>>>
>>>
>>>----- Original Message -----
>>>From: Charles Determan Jr <deter088 at umn.edu>
>>>To: r-help at r-project.org
>>>Cc:
>>>Sent: Wednesday, October 17, 2012 3:42 PM
>>>Subject: [R] cut2 error
>>>
>>>To R users,
>>>
>>>I am trying to use cut2 function from the 'Hmisc' library.  However, when I
>>>try and run the function on the following variable, I get an error message
>>>(displayed below).  I suspect it is because of the NA but I have no idea
>>>how to address the error.  Many thanks to any insights.
>>>
>>>structure(list(var1 = c(97, 97, 98, 98, 97, 99, 97,
>>>98, 99, 98, 99, 98, 98, 97, 97, 98, 99, 98, 96, 98, 98, 99, 98,
>>>98, 99, 99, 98, 99, 98, 99, 99, 99, 99, 98, 99, 96, 99, 98, 98,
>>>99, 97, 98, 99, 99, 97, 99, 99, 98, 98, 98, 99, NA, 99, 98, 98,
>>>98, 98, 98, 98, 98, 99, 99, 98, 99, 99, 98, 98, 99, 99, 97, 98,
>>>98, 98, 99, 98, 98, 98, 99, 98, 98)), .Names = "var1", row.names = c(NA,
>>>80L), class = "data.frame")
>>>
>>>cut2(dat[,1], g=4)
>>>
>>>Warning message:
>>>In min(xx[xx > upper]) : no non-missing arguments to min; returning Inf
>>>
>>>Regards,
>>>Charles
>>>
>>>   [[alternative HTML version deleted]]
>>>
>>>______________________________________________
>>>R-help at r-project.org mailing list
>>>https://stat.ethz.ch/mailman/listinfo/r-help
>>>PLEASE do read the posting guide
>>>http://www.R-project.org/posting-guide.html
>>>and provide commented, minimal, self-contained, reproducible code.
>>>
>>>
>>>
>>        [[alternative HTML version deleted]]
>>
>>______________________________________________
>>R-help at r-project.org mailing list
>>https://stat.ethz.ch/mailman/listinfo/r-help
>>PLEASE do read the posting guide http://www.R-project.org/posting-guide.html
>>and provide commented, minimal, self-contained, reproducible code.
>>
>
David Winsemius, MD
>Alameda, CA, USA
>
>




More information about the R-help mailing list