[R] ifelse reformulation

Pieter Schoonees schoonees at ese.eur.nl
Fri Oct 12 17:58:29 CEST 2012


You can use subscripting on the matrix, e.g. ind <- test == 40 and the test[ind] <- 1. Just deal with the "id" column when you set the rest to 0.

> -----Original Message-----
> From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-
> project.org] On Behalf Of brunosm
> Sent: Friday 12 October 2012 11:51
> To: r-help at r-project.org
> Subject: [R] ifelse reformulation
> 
> Hi, i'm trying to simplify some R code but i got stucked in this:
> 
> test<-data.frame(cbind(id,x1,x2,x3,x4,x5,x6,x7))
> test
> 
> > test
>    id x1 x2 x3 x4 x5 x6 x7
> 1   1 36 26 21 32 31 27 31
> 2   2 45 21 46 50 22 36 29
> 3   3 49 47 35 44 33 31 46
> 4   4 42 32 38 28 39 45 32
> 5   5 29 42 39 48 25 35 34
> 6   6 39 31 30 37 46 43 44
> 7   7 41 40 25 23 42 40 24
> 8   8 27 29 47 34 26 38 28
> 9   9 25 35 29 36 43 34 23
> 10 10 24 44 37 26 27 46 22
> 11 11 38 50 32 49 37 24 40
> 12 12 20 34 48 25 30 41 36
> 13 13 26 46 20 40 29 20 43
> 14 14 33 37 49 31 47 30 30
> 15 15 43 39 27 35 48 47 27
> 
> count40<-
> ifelse(test$x1==40|test$x2==40|test$x3==40|test$x4==40|test$x5==40|test
> $x6==40|test$x7==40,0,1)
> count40
> 
> I'm trying to remake that ifelse. If any variable from x1 to x7 equals
> to 40
> --> 0, else --> 1
> 
> I was trying to do something like:
> 
> count40aux<-ifelse(test[,2:8]==40,0,1)
> count40aux
> 
> It doesn't work as i expected...
> 
> Can anyone help me please?
> 
> Regards,
> 
> Bruno
> 
> 
> 
> 
> 
> --
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> reformulation-tp4645981.html
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> 
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