[R] ifelse reformulation

[arun]

HI, 
Try this: 
count40<- ifelse(test1$x3==40|test1$x4==40|test1$x5==40,0,1) 
count40 
# [1] 1 1 1 1 1 1 1 1 1 1 1 1 0 1 1 
as.vector(apply(test1,1,function(x) ifelse(any(x[4:6]==40),0,1))) 
# [1] 1 1 1 1 1 1 1 1 1 1 1 1 0 1 1 
A.K. 



----- Original Message -----
From: brunosm <brunosm87 at gmail.com>
To: r-help at r-project.org
Cc: 
Sent: Friday, October 12, 2012 10:18 AM
Subject: Re: [R] ifelse reformulation

That was exacly what i was looking for! Thanks a lot!
Cheers!



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