[R] loop for column substraction of a matrix

[Rui Barradas]

Hello,

1. Let me refrase it a bit. For each column, sum all others and take the 
symmetric.


mat <- matrix(1:30, ncol = 3)
sapply(seq_len(ncol(mat)), function(i) -rowSums(mat[, -i]))


2. write.table (maybe using sep = "\t" ?) and send the file to printer.

Hope this helps,

Rui Barradas

Em 05-10-2012 21:05, eliza botto escreveu:
> Dear useRs,
>
>
> I have a matrix with 38 columns and 365 rows. what i want to do is the following.....
>
> 1. subtracting from each column, first itself and then all the remaining columns. More precisely, from column number 1, i will first subtract itself(column 1) and then the remaining 37 columns. Afterwards i will take column number 2 and do the same. In this way i want to proceed till 38th column.
> 2. i want to print the resulting matrix on A4 paper.
>
> Bundle of thanks in advance.
>
> best regards
> eliza
>
>
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