[R] splitting a string by space except when contained within quotes

[arun]

Hi,

You could also do this:
 res<-unlist(strsplit(str,"[\"]"))
 res1<-res[res!=" "]
res2<-c(unlist(strsplit(res1[grepl("\\s+$",res1)]," ")),res1[!grepl("\\s+$",res1)])
res2
#[1] "rainfall"        "snowfall"        "Channel storage" "Rivulet storage"
A.K.




----- Original Message -----
From: downtowater <downtowater at yahoo.ca>
To: r-help at r-project.org
Cc: 
Sent: Thursday, November 29, 2012 9:43 AM
Subject: [R] splitting a string by space except when contained within quotes

I've been trying to split a space delimited string with double-quotes in R
for some time but without success. An example of a string is as follows:

/rainfall snowfall "Channel storage" "Rivulet storage"/

It's important for us because these are column headings that must match the
subsequent data. 

Here is some code I've been trying:

str <- 'rainfall snowfall "Channel storage" "Rivulet storage"'
regex <- "[^\\s\"']+|\"([^\"]*)\""
split <- strsplit(str, regex, perl=T)
what I would like is

[1] "rainfall" "snowfall" "Channel storage" "Rivulet storage"

but what I get is:

[1] ""  " " " " " "

The vector is the right length (which is encouraging) but of course the
strings are empty or contain a single space. Any suggestions?

Thanks in advance!



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