[R] printing difftime summary
Sam Steingold
sds at gnu.org
Tue Nov 27 01:08:48 CET 2012
Thanks a lot - almost there!
--8<---------------cut here---------------start------------->8---
format.summary.difftime <- function(sd, ...) {
t <- matrix(sd$string)
rownames(t) <- rownames(sd)
print(t)
format(as.table(t))
}
print.summary.difftime <- function (sd, ...) {
print(format(sd), quote=FALSE)
invisible(sd)
}
--8<---------------cut here---------------end--------------->8---
this almost works:
--8<---------------cut here---------------start------------->8---
> summary(delays)
share.id min max
12cf12372b87cce9: 1 NULL:492.00 ms NULL:492.00 ms
12cf36060bdb9581: 1 NULL:3.70 min NULL:21.80 min
12d2665c906bb232: 1 NULL:20.32 min NULL:3.26 hrs
12d2802f1435b4cd: 1 NULL:5.52 hrs NULL:13.78 hrs
12d292988f5f8422: 1 NULL:2.81 hrs NULL:16.20 hrs
12d29dd2894e2790: 1 NULL:6.95 days NULL:6.98 days
--8<---------------cut here---------------end--------------->8---
why do I see NULLs?!
--8<---------------cut here---------------start------------->8---
> t <- matrix(sd$string)
> rownames(t) <- rownames(sd)
> t
[,1]
Min. "492.00 ms"
1st Qu. "3.70 min"
Median "20.32 min"
Mean "5.52 hrs"
3rd Qu. "2.81 hrs"
Max. "6.95 days"
> as.table(t)
A
Min. 492.00 ms
1st Qu. 3.70 min
Median 20.32 min
Mean 5.52 hrs
3rd Qu. 2.81 hrs
Max. 6.95 days
> format(as.table(t))
A
Min. "492.00 ms"
1st Qu. "3.70 min "
Median "20.32 min"
Mean "5.52 hrs "
3rd Qu. "2.81 hrs "
Max. "6.95 days"
> --8<---------------cut here---------------end--------------->8---
> * William Dunlap <jqhaync at gvopb.pbz> [2012-11-26 23:02:48 +0000]:
>
> It looks like summary.data.frame(d) calls format(d[[i]]) for i in seq_len(ncol(d))
> and pastes the results together into a "table" object for printing. Hence, write
> a format.summary.difftime if you want objects of class "summary.difftime" (which
> I assume summary.difftime produces) to be formatted as you wish when a
> difftime object is in a data.frame. Once you've written it, have your print.summary.difftime
> call it too.
>
> E.g., with the following methods
> summary.difftime <- function(x, ...) {
> ret <- quantile(x, p=(0:2)/2, na.rm=TRUE)
> class(ret) <- c("summary.difftime", class(ret))
> ret
> }
> format.summary.difftime <- function(x, ...) c(Min.Med.Max =
> paste(collapse="...", NextMethod("format")))
> print.summary.difftime <- function(x, ...){ print(format(x), quote=FALSE) ; invisible(x) }
>
> I get
>> d <- data.frame(Num=1:5, Date=as.Date("2012-11-26")+(0:4),
>> Delta=diff(as.Date("2012-11-26")+2^(0:5)))
>> summary(d)
> Num Date Delta
> Min. :1 Min. :2012-11-26 Min.Med.Max: 1 days... 4 days...16 days
> 1st Qu.:2 1st Qu.:2012-11-27
> Median :3 Median :2012-11-28
> Mean :3 Mean :2012-11-28
> 3rd Qu.:4 3rd Qu.:2012-11-29
> Max. :5 Max. :2012-11-30
>> summary(d$Delta)
> Min.Med.Max
> 1 days... 4 days...16 days
>
> My summary.difftime inherits from difftime so the format method is not really
> needed, as format.difftime does a reasonable job (except that it does not copy
> the input names to its output). I put it in to show how it gets called.
>
>
> Bill Dunlap
> Spotfire, TIBCO Software
> wdunlap tibco.com
>
>
>> -----Original Message-----
>> From: r-help-bounces at r-project.org [mailto:r-help-bounces at r-project.org] On Behalf
>> Of Sam Steingold
>> Sent: Monday, November 26, 2012 2:20 PM
>> To: r-help at r-project.org; David Winsemius
>> Subject: Re: [R] printing difftime summary
>>
>> > * David Winsemius <qjvafrzvhf at pbzpnfg.arg> [2012-11-26 08:46:35 -0800]:
>> >
>> > On Nov 26, 2012, at 7:14 AM, Sam Steingold wrote:
>> >
>> >> summary(infl), where infl$delay is a difftime vector, prints
>> >>
>> >> ...
>> >>
>> >> delay
>> >> string:c("492.00 ms", "18.08 min", "1.77 hrs", "8.20 hrs", "8.13 hrs",
>> >> "6.98 days")
>> >> secs :c(" 0.5", " 1085.1", " 6370.2", " 29534.4", " 29254.0",
>> >> "602949.7")
>> >>
>> >>
>> >>
>> >> instead of something like
>> >>
>> >> delay
>> >> Min.: 492 ms
>> >> 1st Qu.: 18.08 min
>> >>
>> >> &c
>> >>
>> >> so, how do I arrange for a proper printing of difftime summary as a
>> >> part
>> >> of the data frame summary?
>> >
>> > If you like a particular format from an existing print method then why
>> > not look it up and copy the code?
>> >
>> > methods(print)
>>
>> the problem is that I cannot figure out which function prints this:
>>
>> >> delay
>> >> string:c("492.00 ms", "18.08 min", "1.77 hrs", "8.20 hrs", "8.13 hrs",
>> >> "6.98 days")
>> >> secs :c(" 0.5", " 1085.1", " 6370.2", " 29534.4", " 29254.0",
>> >> "602949.7")
>>
>> I added cat()s to print.summary.difftime and I do not see them, so it
>> appears that I have no direct control over how a summary.difftime is
>> printed as a part of a summary of a data.frame.
>>
>>
>> --8<---------------cut here---------------start------------->8---
>> summary.difftime <- function (v, ...) {
>> s <- summary(as.numeric(v), ...)
>> r <- as.data.frame(sapply(s,difftime2string),stringsAsFactors=FALSE)
>> names(r) <- c("string")
>> r[[units(v)]] <- s
>> class(r) <- c("summary.difftime","data.frame")
>> invisible(r)
>> }
>> print.summary.difftime <- function (sd, ...) {
>> cat("[[[print.summary.difftime]]]\n")
>> print(list(...))
>> print.data.frame(sd, ...)
>> }
>> --8<---------------cut here---------------end--------------->8---
>>
>> --
>> Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X 11.0.11103000
>> http://www.childpsy.net/ http://palestinefacts.org http://think-israel.org
>> http://www.memritv.org http://openvotingconsortium.org http://mideasttruth.com
>> The force of gravity doubles when acting on a body on a couch.
>>
>> ______________________________________________
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--
Sam Steingold (http://sds.podval.org/) on Ubuntu 12.04 (precise) X 11.0.11103000
http://www.childpsy.net/ http://openvotingconsortium.org
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There are two ways to write error-free programs; only the third one works.
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