[R] printing difftime summary

[Sam Steingold]

> * David Winsemius <qjvafrzvhf at pbzpnfg.arg> [2012-11-26 08:46:35 -0800]:
>
> On Nov 26, 2012, at 7:14 AM, Sam Steingold wrote:
>
>> summary(infl), where infl$delay is a difftime vector, prints
>>
>> ...
>>
>>    delay
>> string:c("492.00 ms", "18.08 min", "1.77 hrs", "8.20 hrs", "8.13 hrs",
>> "6.98 days")
>> secs  :c("     0.5", "  1085.1", "  6370.2", " 29534.4", " 29254.0",
>> "602949.7")
>>
>>
>>
>> instead of something like
>>
>>   delay
>>   Min.:    492 ms
>>   1st Qu.: 18.08 min
>>
>> &c
>>
>> so, how do I arrange for a proper printing of difftime summary as a
>> part
>> of the data frame summary?
>
> If you like a particular format from an existing print method then why
> not look it up and copy the code?
>
> methods(print)

the problem is that I cannot figure out which function prints this:

>>    delay
>> string:c("492.00 ms", "18.08 min", "1.77 hrs", "8.20 hrs", "8.13 hrs",
>> "6.98 days")
>> secs  :c("     0.5", "  1085.1", "  6370.2", " 29534.4", " 29254.0",
>> "602949.7")

I added cat()s to print.summary.difftime and I do not see them, so it
appears that I have no direct control over how a summary.difftime is
printed as a part of a summary of a data.frame.


--8<---------------cut here---------------start------------->8---
summary.difftime <- function (v, ...) {
  s <- summary(as.numeric(v), ...)
  r <- as.data.frame(sapply(s,difftime2string),stringsAsFactors=FALSE)
  names(r) <- c("string")
  r[[units(v)]] <- s
  class(r) <- c("summary.difftime","data.frame")
  invisible(r)
}
print.summary.difftime <- function (sd, ...) {
  cat("[[[print.summary.difftime]]]\n")
  print(list(...))
  print.data.frame(sd, ...)
}
--8<---------------cut here---------------end--------------->8---

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