[R] Using if

[jim holtman]

Try this (convert the logical TRUE to the value 1):


> EvHint<-c(0, 0, 0, 1, 0, 1, 1, 0, 1, 1, 1, 1, 1, 0, 1, 0, 0, 1, 0, 0)
> MinTex<-c(0, 0, 1, 1, 0, 1, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 1, 0)
>
> RiskTest <- (EvHint == 1 & MinTex == 1) + 0L
> rbind(EvHint, MinTex, RiskTest)
         [,1] [,2] [,3] [,4] [,5] [,6] [,7] [,8] [,9] [,10] [,11]
[,12] [,13] [,14] [,15] [,16]
EvHint      0    0    0    1    0    1    1    0    1     1     1
1     1     0     1     0
MinTex      0    0    1    1    0    1    1    0    0     0     0
1     0     0     0     0
RiskTest    0    0    0    1    0    1    1    0    0     0     0
1     0     0     0     0
         [,17] [,18] [,19] [,20]
EvHint       0     1     0     0
MinTex       0     0     1     0
RiskTest     0     0     0     0
>


On Tue, Nov 20, 2012 at 2:08 PM, Virgile Capo-Chichi
<vcapochichi at gmail.com> wrote:
> Dear R users,
>
> As a new comer to R, I would like to create a new variable using if
> statements but don't know how to do it. Basically, I have two variables
> (EvHint and MinTex). I want to create a third variable called RiskTest.
>
> In SPSS, my syntax would look like
>
> Compute RiskTest=0.
> if (EvHint=1 & MinTex=1) RiskTest=1.
>
> Question: How do I do this with R?
>
> My Data
>
> EvHint<-c(0, 0, 0, 1, 0, 1, 1, 0, 1, 1, 1, 1, 1, 0, 1, 0, 0, 1, 0, 0)
> MinTex<-c(0, 0, 1, 1, 0, 1, 1, 0, 0, 0, 0, 1, 0, 0, 0, 0, 0, 0, 1, 0)
>
> Thanks, V
>
>         [[alternative HTML version deleted]]
>
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-- 
Jim Holtman
Data Munger Guru

What is the problem that you are trying to solve?
Tell me what you want to do, not how you want to do it.