[R] Using cbind to combine data frames and preserve header/names

[Rainer Schuermann]

Not sure where the problem is?

Since you did not provide sample data, I took the iris data set and converted it to your structure:

x <- cbind( iris[5], iris[1:3] )

head( x )
  Species Sepal.Length Sepal.Width Petal.Length
1  setosa          5.1         3.5          1.4
2  setosa          4.9         3.0          1.4
3  setosa          4.7         3.2          1.3
4  setosa          4.6         3.1          1.5
5  setosa          5.0         3.6          1.4
6  setosa          5.4         3.9          1.7

Does that look like your data?

If so, 

xbin <- cbind( x[1], binarize( x[2:4] ) )

gives a result that should look just like what you want:

head( xbin )
  Species Sepal.Length Sepal.Width Petal.Length
1  setosa            1           0            0
2  setosa            1           0            0
3  setosa            1           0            0
4  setosa            1           0            0
5  setosa            1           0            0
6  setosa            1           0            0

Using
xbin <- cbind( x$Species, binarize( x[-1] ) )
doesn't make a difference.

Or did I not understand your problem well?

Rgds,
Rainer



On Saturday 17 November 2012 00:39:02 Brian Feeny wrote:
> I have a dataframe that has a header like so:
> 
> class	value1	value2	value3
> 
> class is a factor
> 
> the actual values in the columns value1, value2 and value3 are 0-255, I wish to binarize these using biclust.
> I can do this like so:
> 
> binarize(dataframe[,-1])
> 
> this will return a dataframe, but then I lose my first column class, so I thought I could combine it like so:
> 
> dataframe <- cbind(dataframe$label, binarize(dataframe[,-1]))
> 
> but then I lose my header (names).............how can I do the above operation and keep my header in tact?
> 
> Basically i just want to binarize everything but the first column (since its a factor column and not numeric).
> 
> Thank you for any help you can give me, I am relatively new to R.
> 
> Brian
> 
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