[R] using lapply with recode

[arun]

HI,
Try this:


 lapply(mylist,function(x) {recode(x[,2],"'QUE'='QC';'Quebec'='QC'")
return(x)})
#$df1
 #   a prov
#1   1  QUE
#2   2  QUE
#3   3  QUE
#4   4  QUE
#5   5  QUE
#6   6   BC
#7   7   BC
#8   8   BC
#9   9   BC
#10 10   BC

#$df2
 #   a   prov
#1   1 Quebec
#2   2 Quebec
#3   3 Quebec
#4   4 Quebec
#5   5 Quebec
#6   6     AB
#7   7     AB
#8   8     AB
#9   9     AB
#10 10     AB
A.K.



----- Original Message -----
From: Simon Kiss <sjkiss at gmail.com>
To: r-help at r-project.org
Cc: 
Sent: Thursday, November 8, 2012 10:06 PM
Subject: [R] using lapply with recode

Hello: 
Forgive me, this is surely a simple question but I can't figure it out, having consulted the help archives and "Data Manipulation With R" (Spector).
I have a list of 11 data frames with one common variable in each (prov). I'd like to use lapply to go through and recode one particular level of that common variable. 
I can get the recode to work, but it only returns the variable that has been recoded.  I need the whole data frame with the recoded variable.

Thank you for your help. Reproducible data and my current code are below.


####Sample Data
mylist<-list(df1=data.frame(a=seq(1,10,1), prov=c(rep('QUE', 5), rep('BC', 5))), df2=data.frame(a=seq(1,10,1), prov=c(rep('Quebec', 5), rep('AB', 5))))
str(mylist)

###My current code
lapply(mylist, function(x) {
recode(x$prov, "'QUE'='QC' ; 'Quebec'='QC'")
}
)

*********************************
Simon J. Kiss, PhD
Assistant Professor, Wilfrid Laurier University
73 George Street
Brantford, Ontario, Canada
N3T 2C9

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