[R] qnorm to a list

[QAMAR MUHAMMAD UZAIR]

dear jim,
thakyou very much for your help. i would really appreciate 
if you give me one more favor. i want to apply qnorm to 
the whole coulmn so that i would have on the x-axis the 
quantile of the lognormal distribution (qnorm(....)) with 
zero-mean and unit-variance, corresponding to excedence 
probabilities F=i/(365+1) with i=1...365.
thanks in advance
bye

On Fri, 25 May 2012 18:15:45 +1000
  Jim Lemon <jim at bitwrit.com.au> wrote:
> On 05/25/2012 02:45 AM, QAMAR MUHAMMAD UZAIR wrote:
>> ...
> > I want to reshape it in the following FORMAT
> >
> >     1967    1968    1969    1970    1971    1972 
>   1973    1974
> > 1    0.87    0.87    0.87    0.87                0.71
> > 2    0.87    0.87    0.87    0.87                0.72
> >
> > OBVIOUSLY, I HAVE A LARGE AMOUNT OF DATA TO WORK 
>WITH.i would also
> > like to take into account the effect of leap year. For 
>example if
> > 1969 in a leap year then the column under it, has to 
>have 1 extra
> > reading.
> 
> Hi Qamar,
> You can do something like this, assuming that your data 
>frame is named "qmu" and the two columns are named "V1" 
>and "V2":
> 
> # extract years from the dates
> qmu$year<-as.numeric(sapply(strsplit(as.character(qmu$V1),"[.]"),"[",3))
> # get a vector of the unique years
> uyears<-unique(qmu$year)
> # make an empty list
> newqmu<-list()
> # populate the list year by year
> for(i in 1:length(uyears)) 
>newqmu[[i]]<-qmu$V2[qmu$year==uyears[i]]
> 
> This will give you a list with the same characteristics 
>as you described. You can't have a data frame with 
>different column lengths, so you would have to pad the 
>shorter columns with NA values if you want a data frame.
> 
> Jim
> 
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